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3 years ago

12

Harry rides his bike 25 3 over 8 karen rides her bike 25 3 over 8 Who rode further

1 answer:

Anon25 [30]3 years ago

5 0

I would think they go the same.

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Solve the following equation by factoring:9x^2-3x-2=0

olya-2409 [2.1K]

Answer:

The two roots of the quadratic equation are

$x_1= - \frac{1}{3} \text{ and } x_2= \frac{2}{3}$

Step-by-step explanation:

Original quadratic equation is $9x^{2}-3x-2=0$

Divide both sides by 9:

$x^{2} - \frac{x}{3} - \frac{2}{9}=0$

Add $\frac{2}{9}$ to both sides to get rid of the constant on the LHS

$x^{2} - \frac{x}{3} - \frac{2}{9}+\frac{2}{9}=\frac{2}{9}$ ==> $x^{2} - \frac{x}{3}=\frac{2}{9}$

Add $\frac{1}{36}$ to both sides

$x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{2}{9} +\frac{1}{36}$

This simplifies to

$x^{2} - \frac{x}{3}+\frac{1}{36}=\frac{1}{4}$

Noting that (a + b)² = a² + 2ab + b²

If we set a = x and b = $\frac{1}{6}\right)$ we can see that

$\left(x - \frac{1}{6}\right)^2$ = $x^2 - 2.x. (-\frac{1}{6}) + \frac{1}{36} = x^{2} - \frac{x}{3}+\frac{1}{36}$

So

$\left(x - \frac{1}{6}\right)^2=\frac{1}{4}$

Taking square roots on both sides

$\left(x - \frac{1}{6}\right)^2= \pm\frac{1}{4}$

So the two roots or solutions of the equation are

$x - \frac{1}{6}=-\sqrt{\frac{1}{4}}$ and $x - \frac{1}{6}=\sqrt{\frac{1}{4}}$

$\sqrt{\frac{1}{4}} = \frac{1}{2}$

So the two roots are

$x_1=\frac{1}{6} - \frac{1}{2} = -\frac{1}{3}$

and

$x_2=\frac{1}{6} + \frac{1}{2} = \frac{2}{3}$

7 0

1 year ago

You have 6 green marbles, 23 blue marbles, and 18 red marbles. what is the probability of choosing a red marble. express your an

AysviL [449]

The probability of choosing a red marble is 18/47.

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3 years ago

3x + 2 = 2x + 6<br><br><br> Please hurry

telo118 [61]

Answer:

Solve for x by simplifying both sides of the equation, then isolating the variable.

x = 4

Step-by-step explanation:

I hope this helps! Have a good day!

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3 years ago

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Geometry help will give brainliest i was wrong

skelet666 [1.2K]

The reason you got it wrong is because you solved for the side a instead of the angle Z, which was what the question asked you to solve for. You can find Z by doing cos Z = 12/35, which will get you cos Z = 0.343, and Z will be equal to about 70º.

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3 years ago

For any positive numbers a, b, and d, with b≠1, logb(a·d) = _____.

Katena32 [7]

Answer:

logb a* logb d

or

logb a - logb d

or

logb(a*d)

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3 years ago

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