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Gemiola [76]
3 years ago
7

use the power-reducing formulas to rewrite the expression in terms of the first power of the cosine . . sin^6 x

Mathematics
1 answer:
andrey2020 [161]3 years ago
4 0
<span>1/128 (3 - 4 Cos[4 x] + Cos[8 x])</span>( sin^2(x) )^2 cos^4(x) 

<span>( (1 - cos^2(x) )^2 cos^4(x) </span>

<span>(1 - 2cos^2(x) + cos^4(x) ) cos^4(x) </span>

<span>cos^4(x) - 2cos^6(x) + cos^8(x) </span>

<span>( cos^2(x) )^2 - 2( cos^2(x) )^3 + ( cos^2(x) )^4 <==> knowing the identity; cos^2(x) = (1/2) * (1 + cos(2x)) </span>

<span>( (1/2) * (1 + cos(2x)) )^2 - 2( (1/2) * (1 + cos(2x)) )^3 + ( (1/2) * (1 + cos(2x)) )^4 </span>

( (1/4) * (1 + 2cos(2x) + cos^2(2x) )) - 2( (1/8) * (cos^3(2x) + 3cos^2(2x) + 3cos(2x) + 1) + ( (1/16) * cos^4(2x) + 4cos^3(2x) + 6cos^2(2x) + 4cos(2x) + 1) 
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Stacey wishes to make a hamburger which is lower in fat without having to give up the great taste. She purchases 5 pounds of gro
STALIN [3.7K]

Answer:

%P = 8%

the percentage of fat in the mixture is 8%

Step-by-step explanation:

Given;

The percentage of fat in the mixture is;

%P = total mass of fat in mixture/total mass of mixture × 100%

%P = F/T × 100% ….....1

Mass of fat in mixture is;

She purchases 5 pounds of ground beef which is 15% fat

F1 = 15% of 5 pounds = 0.15×5 pounds

F1 = 0.75 pound

and combines it with 7 pounds of ground turkey which is only 3% fat

F2 = 3% of 7 pounds = 0.03 × 7

F2 = 0.21 pound

Total mass F = F1 + F2

F = 0.75+0.21

F = 0.96 pound

Total mass of mixture T = 5 + 7 pounds

T = 12 pounds.

From equation 1,

%P = F/T × 100%

%P = 0.96/12 × 100%

%P = 0.08×100%

%P = 8%

the percentage of fat in the mixture is 8%

5 0
3 years ago
³√73-(-3)², calculate the value​
Vitek1552 [10]
The value of this equation is: 4
Answer: 4
6 0
3 years ago
Find the value of n.
Yuki888 [10]
The answer is 30. You are welcome
5 0
3 years ago
Read 2 more answers
Y=-x^2+2x+10<br> y=x+2<br><br> Substitution <br> Please show your work<br> Need ASAP
erik [133]

Answer:

The solutions of the system of equations are the points

(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})  

(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})  

Step-by-step explanation:

we have

y=-x^{2} +2x+10 ----> equation A

y=x+2 ----> equation B

Solve the system by substitution

substitute equation B in equation A

x+2=-x^{2} +2x+10

solve for x

-x^{2} +2x+10-x-2=0

-x^{2} +x+8=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-x^{2} +x+8=0

so

a=-1\\b=1\\c=8

substitute in the formula

x=\frac{-1\pm\sqrt{1^{2}-4(-1)(8)}} {2(-1)}

x=\frac{-1\pm\sqrt{33}} {-2}

x=\frac{-1+\sqrt{33}} {-2}  -----> x=\frac{1-\sqrt{33}} {2}  

x=\frac{-1-\sqrt{33}} {-2}  -----> x=\frac{1+\sqrt{33}} {2}  

<em>Find the values of y</em>

For x=\frac{1-\sqrt{33}} {2}  

y=x+2

y=\frac{1-\sqrt{33}} {2}+2  ---->y=\frac{5-\sqrt{33}} {2}  

For x=\frac{1+\sqrt{33}} {2}  

y=x+2

y=\frac{1+\sqrt{33}} {2}+2  ---->y=\frac{5+\sqrt{33}} {2}  

therefore

The solutions of the system of equations are the points

(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})  

(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})  

5 0
2 years ago
Solve for a<br><br> 5 + 7a = 19
Bess [88]
A = 2 all you gotta do is 7 x 2 which is 14 and add 5 to it which equals 19
8 0
2 years ago
Read 2 more answers
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