Answer:
See below ~
Step-by-step explanation:
<u>Problem 9</u>
- h(1/8) = 3(1/8) + 1/4
- h(1/8) = 3/8 + 2/8
- h(1/8) = <u>5/8</u>
<u></u>
<u>Problem 10</u>
- Q(k) = k - 3 / 2
- -4 = k - 3 / 2
- -8 = k - 3
- k = -8 + 3
- k = <u>-5</u>
Answer:
C = 20
Step-by-step explanation:
What happens if simultaneous Equations have two of the same variable like below? How would I solve it?
6A + 4B + 5C = 390
6A + 4B + 5.75C = 405
Step 1
We solve for C first
6A + 4B + 5C = 390....Equation 1
6A + 4B + 5.75C = 405... Equation 2
We substract Equation 1 from Equation 2
0.75C = 15
C = 15/0.75
C = 20
<h3>
Answer: It increases by 1</h3>
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Explanation:
To compute the mean, we first add up the numbers
5+3+5+3+4 = 20
Then divide by 5 since there are 5 numbers in the set
20/5 = 4
The mean is 4.
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Now replace one of the '3's with 8 and recompute the mean
5+8+5+3+4 = 25
25/5 = 5
The mean is now 5.
The old mean in the previous section was 4.
The mean has increased by 1 since 5-4 = 1.
Side note: The increase from 3 to 8 is +5, which when dividing by 5, we're basically incrementing the mean by +1.
Answer:
20
Step-by-step explanation:
(2√5)²=
4*5=20
Answer:
12.449899598
Step-by-step explanation:
You would use pythagoras thereom.
C^2=A^2+B^2
The hypotenuse is C (which is the longest side of the triangle - 18).
18×18=13×13+B^2
324=169+B^2
324-169=B^2
155=B^2
Square root B to get B on it's own which would be 12.449899598.
