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miskamm [114]
3 years ago
13

Can you please help me?

Mathematics
1 answer:
Tresset [83]3 years ago
6 0

Answer:

Use trigonometry

Tan-theta=p/b

tan53= 14/RT

RTtan53=14

RT=14/tan53

RT=10.55 cm

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Answer - 42

Expression Evaluated - 2 Times 17 Plus 8

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Help ASPP<br><br>-3/5 x = 18 <br>-30<br>-10 4/5<br>10 4/5<br>30​
kompoz [17]

Answer:

-30

Step-by-step explanation:

move and divide -3/5 to the right side

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5 0
3 years ago
*I WILL MARK YOU BRAINLIEST!!!!!*
AlekseyPX
<h2><em> </em><em>Answer:</em></h2>

<em>-</em><em>3</em>

<em>Explanation</em><em>:</em>

<em>Rate </em><em>of </em><em>change </em><em>in </em><em>the </em><em>interval</em>

<em>X=</em><em>0</em><em> </em><em>to </em><em>X=</em><em>3</em><em> </em><em>is </em><em>given </em><em>by,</em>

<em>r =  \frac{f(3) - f(0)}{3 - 0}  \\ here \\ f(3) = 1 \\ f(0) = 10 \\ r =  \frac{1 - 10}{3}  \\  \:  \:  \:  =  \frac{ - 9}{  3}  \\  \:  \:  \:  \:  =  - 3 \\ hope \: it \: helps.....</em>

4 0
3 years ago
6. A car dealership would like to estimate the mean mpg of its new model car with 90% confidence. The population is normally dis
Yakvenalex [24]

Answer:

92.9997<\mu<99.5203

Step-by-step explanation:

Using the formula for calculating the confidence interval expressed as:

CI = xbar ± Z * S/√n where;

xbar is the sample mean

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S is the sample standard deviation

n is the sample size

Given parameters

xbar = 96.52

Z at 90% CI = 1.645

S = 10.70.

n = 25

Required

90% confidence interval for the population mean using the sample data.

Substituting the given parameters into the formula, we will have;

CI = 96.52 ± (1.645 * 10.70/√25)

CI = 96.52 ± (1.645 * 10.70/5)

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CI = 96.52 ± (3.5203)

CI = (96.52-3.5203, 96.52+3.5203)

CI = (92.9997, 99.5203)

<em>Hence a 90% confidence interval for the population mean using this sample data is 92.9997<</em>\mu<em><99.5203</em>

4 0
3 years ago
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