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DerKrebs [107]
3 years ago
15

Jason and Karina have matching gardens Jason plants 2/3 of his garden with roses Karina's garden is divided into ninths how much

garden must she plant to have the same amount.
Mathematics
1 answer:
olganol [36]3 years ago
5 0

Answer:

6/9

Step-by-step explanation:

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Probability of a coin landing on heads
Viefleur [7K]

Answer:

The answer would be 50% or 1/2

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Factor by grouping: 4x3 - 6x2 + 10x - 15.
BlackZzzverrR [31]
4x³ - 6x² + 10x - 15
2x²(2x) - 2x²(3) + 5(2x) - 5(3)
2x²(2x - 3) + 5(2x - 3)
(2x² + 5)(2x - 3)

The answer is B.
8 0
3 years ago
Solve the combined inequality and describe the graph of the solution.
Vikki [24]
I hope this helps you



4x>-4 x>-1



8x <32 x <4


-1 <x <4
3 0
3 years ago
Someone please help me
allsm [11]

Answer:

Solutions: x = \frac{-3}{ 4} + i \sqrt{39},  x = \frac{-3}{4} - i \sqrt{39}

Step-by-step explanation:

Given the quadratic equation, 2x² + 3x + 6 = 0, where a =2, b = 3, and c = 6:

Use the <u>quadratic equation</u> and substitute the values for a, b, and c to solve for the solutions:

x = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}

x = \frac{-3 +/- \sqrt{3^{2} - 4(2)(6)} }{2(2)}

x = \frac{-3 +/- \sqrt{9- 48} }{4}

x = \frac{-3 +/- \sqrt{-39} }{4}

x = \frac{-3 + i \sqrt{39} }{4}, x = \frac{-3 - i \sqrt{39} }{4}

Therefore, the solutions to the given quadratic equation are:

x = -\frac{3}{ 4} + i \sqrt{39} ,   x = -\frac{3}{4} - i \sqrt{39}

4 0
2 years ago
How many planes contain each line and point?
nikitadnepr [17]

There are infinite many planes that contain each line and point

<h3>How to determine the number of planes?</h3>

The given parameters are given as:

  • Line KL and G
  • Line JI and G

As a general rule, a line and a point can be used to draw as many planes as possible

This means that there are infinite many planes possible

Hence, there are infinite many planes that contain each line and point

Read more about planes and points at:

brainly.com/question/14366932

#SPJ1

8 0
2 years ago
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