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Margaret [11]
3 years ago
6

3a+8+2ax≥3ax-4a what is a

Mathematics
1 answer:
xeze [42]3 years ago
7 0

Answer:

A=3 I'm 95% sure but if you're not sure then use PEMDAS

P-parentheses

E-exponets

M-multiply

D-divide

A-add

S-subtract

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Please help I will give 10 points​
vazorg [7]

Answer:

x = 13.75

Step-by-step explanation:

a right-angled triangle.

so, we use Pythagoras

c² = a² + b²

where c is the Hypotenuse (the side opposite of the 90 degree angle).

so, in our case

17² = 10² + x²

289 = 100 + x²

189 = x²

x = 13.75

3 0
2 years ago
This is confusing I need help .
Fittoniya [83]

Answer:

  • x = 54
  • angle ACD = 124°

Step-by-step explanation:

The rule is that the exterior angle (ACD) is equal to the sum of the remote interior angles (the two marked angles on the right).

You are expected to use this relation to write and solve an equation.

  exterior angle = angle D + angle B

  (2x +16) = 58 + (x+12)

  2x +16 = x +70

  x + 16 = 70

  x = 54

Then angle ACD is ...

  angle ACD = (2x +16)° = (2·54 +16)°

  angle ACD = 124°

8 0
2 years ago
The midsegment of a trapezoid is 11 cm in length. If one of the trapezoid's bases is 17 cm long, what is the length of the other
vagabundo [1.1K]

Answer:

x must be 5

Step-by-step explanation:

Recall that the area formula for a trapezoid is

A = (average of base lengths)(width)

Here we have

                                                                   17 cm + x

      (average of base lengths) = 11 cm = ----------------

                                                                           2

So 2(11 cm) = 17 cm + x, or

      22 cm = 17 cm + x

Then x must be 5.

7 0
3 years ago
What is the value of x ?<br> 7x– 5 = 4x - 14
ruslelena [56]

Answer: X is equal to -3

Step-by-step explanation: I isolated x and then divided both sides by x

7 0
2 years ago
The shape shown in the diagram below is made up from a hemisphere on top of a cylinder.
Sedbober [7]
Lal,sos;a;d Lal,sos;a;d Lal,sos;a;d Lal,sos;a;d Lal,sos;a;d Lal,sos;a;d Lal,sos;a;d Lal,sos;a;d Lal,sos;a;d Lal,sos;a;d Lal,sos;a;d Lal,sos;a;d Lal,sos;a;d Lal,sos;a;d Lal,sos;a;d Lal,sos;a;d Lal,sos;a;d Lal,sos;a;d Lal,sos;a;d Lal,sos;a;d Lal,sos;a;d Lal,sos;a;d Lal,sos;a;d Lal,sos;a;d Lal,sos;a;d Lal,sos;a;d
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3 years ago
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