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Margaret [11]
3 years ago
6

3a+8+2ax≥3ax-4a what is a

Mathematics
1 answer:
xeze [42]3 years ago
7 0

Answer:

A=3 I'm 95% sure but if you're not sure then use PEMDAS

P-parentheses

E-exponets

M-multiply

D-divide

A-add

S-subtract

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çok üzgünüm ama biz daha bu konuya geçmedik

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2 years ago
Max is organizing a trip to the airport for a
LuckyWell [14K]

Answer:

<em>$738</em>

Step-by-step explanation:

Uber X costs $40

Max orders 9

$40.00·9=$360.00

Uber XL costs $63

Max orders 6

$63.00·6=$378

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<u>Hope this is helpful :-)</u>

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2 years ago
¡Please answer!<br>¿What is a circle?.​
aksik [14]

Answer:

A circle is a shape.

Step-by-step explanation:

In geometry circles are known for you to solve the radius wit the formula      A= π r^2

A circle is a shape consisting of all points in a plane that are a given distance from a given point, the centre; equivalently it is the curve traced out by a point that moves in a plane so that its distance from a given point is constant.

4 0
3 years ago
Consider a sample with data values of 27, 25, 20, 15, 30, 34, 28, and 25. Compute the range, interquartile range, variance, and
Valentin [98]

So we have a set of integers,

X=\{15,20,25,25,27,28,30,34\}

And we need to compute some stats.

First the range,

The range of data set is difference between the maximum and the minimum of the data set.

So the minimum is 15 and maximum is 34 therefore the range is 34 - 15 = 19.

Second the interquartile range,

The interquartile range of data set is the difference of the first and third quartiles.

First quartile is the value separating the lower quarter and higher three - quarters of the set. The first quartile is computed by taking median of the lower half of the sorted set. This is 15, 20, 25, 25 and it's median is 22.5

Third quartile is therefore the median of 27, 28, 30, 34 which is 29.

Next up, variance.

The variance of set measures how much data is spread out. For data set x_1,\dots, x_n with an average a,

\mathsf{var}(X)=\Sigma_{i=1}^{n}\dfrac{(x_i-a)^2}{n-1}

So first compute the average value which is actually a mean,

a=\dfrac{1}{2}\Sigma_{i=1}^{n}a_i

The sum \Sigma_{i=1}^{n}a_i of numbers in set is 204.

Divide this by number of elements in the set (8).

a=\dfrac{204}{8}=25.5

Then compute the variance,

\mathsf{var}(X)=\dfrac{\Sigma_{i=1}^{n}(x_i-a)^2}{n-1}\approx\boxed{34.57}

And finally standard deviation,

Since have computed variance the standard deviation is nothing too hard. It's defined as a square root of variance,

\mathsf{sde}(X)=\sqrt{\dfrac{\Sigma_{i=1}^{n}(x_i-a)^2}{n-1}}=\sqrt{34.57}\approx\boxed{5.88}

Hope this helps.

r3t40

6 0
2 years ago
Parallelogram JKLM<br>-<br>72°)<br>560<br>270M<br>@ 300<br>627<br>What is mZLIM?<br>© 250<br>235​
Irina-Kira [14]

Answer:7

Step-by-step explanation:

8 0
3 years ago
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