Answer:
50%
Explanation:
Glucose is a simple sugar with a total of 6 carbon atoms in its structure. Pyruvate has a total of three carbon atoms. Two molecules of pyruvate are obtained per glucose by glycolysis. None of the carbon of glucose is released in the form of CO2 during glycolysis. Therefore, the radio-labeled C-1 of glucose will be the component of the carbon skeleton of one of the total of two pyruvate molecules produced during glycolysis. So, 50% of the pyruvate will exhibit radioactivity.
Answer: <em>Interphase is the phase in the cell cycle during which cells that will undergo mitosis prepare for division. In interphase, DNA of the cell copies. After that cell undergoes mitosis, which is the phase of the cell cycle during which cell divides on two identical. Mitosis consists of four phases:</em>
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<em>1. Prophase: Chromatin in the nucleus condenses and chromosomes pair up
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<em>2. Metaphase: Chromosomes line up at the centre of the cell.
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<em>3. Anaphase: The sister chromatids separate from each other to the opposite sides of the cells.
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<em>4. Telophase and Cytokinesis: Membrane forms around each set of chromosomes on two opposite sides of the cells and cell divides into two identical daughter cells.</em>
Answer:
In conservation biology, a flagship species is a species chosen to raise support for biodiversity conservation in a given place or social context.
Explanation:
I just know ig ...
Answer: peptide bonds
Peptide bonds formation is the linking of amino acids
Answer:
it is the vector b hope this helps
Explanation:
