def dx(fn, x, delta=0.001):
return (fn(x+delta) - fn(x))/delta
def solve(fn, value, x=0.5, maxtries=1000, maxerr=0.00001):
for tries in xrange(maxtries):
err = fn(x) - value
if abs(err) < maxerr:
return x
slope = dx(fn, x)
x -= err/slope
raise ValueError('no solution found')
The python code which can be used to read dates from input, one date per line and each date's format must be as follows: March 1, 1990, is:
<h3>Python code</h3>
import datetime
inputs = []
result = []
#read the inputs
date = input()
inputs.append(date)
while not date == "-1":
date = input()
inputs.append(date)
#check if the input is in the correct format and convert it.
for date_text in inputs:
try:
date_text = datetime.datetime.strptime(date_text,"%d %B, %Y")
result.append(date_text.strftime("%d/%m/%Y"))
except ValueError:
pass
print(*result, sep = "\n")
The above code would parse the string and extract the date. The split() method was used to break the input into tokens.
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Answer:
To obtain VLAN information from directly connected switches. To determine the status of network services on a remote device. To determine the status of the routing protocols between directly connected routers .
Explanation:
