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3 years ago

Which are among the ways you can use bitlocker encryption? (choose all that apply?

1 answer:

3 0

There is a lot of ways that you can use the bit locker encryption. Some are when you are authenticating your computer using a TPM. Or when you are authenticating your account using a USB Flash drive, and most on the phones authentication through text messages and all.

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Darian is preparing for a presentation about the poor condition of the locker rooms at school. Match each of the key components

Gemiola [76]

Answer:

Purpose - To paurswade the board to change the conditions of the locker room

Topic - Locker room condition

Method - Electronic Slideshow

Audience - School Board

7 0

2 years ago

What is the type of data in the list [103, 405, 527, 396, 503]?

Mariulka [41]

Answer:

alphanumeric.........

3 0

2 years ago

Read 2 more answers

When a percentage of the smallest and largest values are deleted from a data set, the mean of the remaining data values is the a

xz_007 [3.2K]

Answer:

Correct option C

Trimmed mean

Explanation:

A trimmed mean is a method of averaging that removes a small designated percentage of the largest and smallest values before calculating the mean.

Trimmed mean helps eliminate the influence of data points on the tails that may unfairly affect the traditional mean.

Trimmed means are used in reporting economic data in order to smooth the results and paint a more realistic picture.

5 0

3 years ago

Note: You can use a word document to write your answers and copy-paste your answer to the area specified. a. (5 points) Convert

MrMuchimi

Answer:

$EA9_{16} = 3753$

$CB2_{16} = 3250$

$(1011 1110 1101 1011 1010)_2 = 781754$

$(1010 1000 1011 1000 1110 1101)_2 = 11057389$

$(1011 1110 1101 1011 1010)_2 = BEDBA$

$(1010 1000 1011 1000 1110 1101)_2 = A8B8ED$

$74510_8= 221416$

$67210_8 = 203212$

Explanation:

Solving (a): To base 10

$(i)\ EA9_{16$

We simply multiply each digit by a base of 16 to the power of their position.

i.e.

$EA9_{16} = E * 16^2 + A * 16^1 + 9 * 16^0$

$EA9_{16} = E * 256 + A * 16 + 9 * 1$

In hexadecimal

$A = 10; E = 14$

So:

$EA9_{16} = 14 * 256 + 10 * 16 + 9 * 1$

$EA9_{16} = 3753$

$(ii)\ CB2_{16}$

This gives:

$CB2_{16} = C * 16^2 + B * 16^1 + 2 * 16^0$

$CB2_{16} = C * 256 + B * 16 + 2 * 1$

In hexadecimal

$C = 12; B =11$

So:

$CB2_{16} = 12 * 256 + 11 * 16 + 2 * 1$

$CB2_{16} = 3250$

Solving (b): To base 10

$(i)\ (1011 1110 1101 1011 1010)_2$

We simply multiply each digit by a base of 2 to the power of their position.

i.e.

$(1011 1110 1101 1011 1010)_2 = 1 * 2^{19} + 0 * 2^{18} + 1 * 2^{17} + 1 * 2^{16} +1 * 2^{15} + 1 * 2^{14} + 1 * 2^{13} + 0 * 2^{12} + 1 * 2^{11} + 1 * 2^{10} + 0 * 2^9 + 1 * 2^8 +1 * 2^7 + 0 * 2^6 + 1 * 2^5 + 1 * 2^4 + 1 * 2^3 + 0 * 2^2 + 1 * 2^1 + 0 * 2^0$

$(1011 1110 1101 1011 1010)_2 = 781754$

$(ii)\ (1010 1000 1011 1000 1110 1101)_2$

$(1010 1000 1011 1000 1110 1101)_2 = 1 * 2^{23} + 0 * 2^{22} + 1 * 2^{21} + 0 * 2^{20} +1 * 2^{19} + 0 * 2^{18} + 0 * 2^{17} + 0 * 2^{16} + 1 * 2^{15} + 0 * 2^{14} + 1 * 2^{13} + 1 * 2^{12} +1 * 2^{11} + 0 * 2^{10} + 0 * 2^9 + 0 * 2^8 + 1 * 2^7 + 1 * 2^6 + 1 * 2^5 + 0 * 2^4 + 1*2^3 + 1 * 2^2 + 0 * 2^1 + 1 * 2^0$

$(1010 1000 1011 1000 1110 1101)_2 = 11057389$

Solving (c): To base 16

$i.\ (1011 1110 1101 1011 1010)_2$

First, convert to base 10

In (b)

$(1011 1110 1101 1011 1010)_2 = 781754$

Next, is to divide 781754 by 16 and keep track of the remainder

$781754/16\ |\ 48859\ R\ 10$

$48859/16\ |\ 3053\ R\ 11$

$3053/16\ |\ 190\ R\ 13$

$190/16\ |\ 11\ R\ 14$

$11/16\ |\ 0\ R\ 11$

Write out the remainder from bottom to top

$(11)(14)(13)(11)(10)$

In hexadecimal

$A = 10; B = 11; C = 12; D = 13; E = 14; F = 15.$

$(11)(14)(13)(11)(10)=BEDBA$

So:

$(1011 1110 1101 1011 1010)_2 = BEDBA$

$ii.\ (1010 1000 1011 1000 1110 1101)_2$

In b

$(1010 1000 1011 1000 1110 1101)_2 = 11057389$

Next, is to divide 11057389 by 16 and keep track of the remainder

$11057389/16\ |\ 691086\ R\ 13$

$691086/16\ |\ 43192\ R\ 14$

$43192/16\ |\ 2699\ R\ 8$

$2699/16\ |\ 168\ R\ 11$

$168/16\ |\ 10\ R\ 8$

$10/16\ |\ 0\ R\ 10$

Write out the remainder from bottom to top

$(10)8(11)8(14)(13)$

In hexadecimal

$A = 10; B = 11; C = 12; D = 13; E = 14; F = 15.$

$(10)8(11)8(14)(13) = A8B8ED$

So:

$(1010 1000 1011 1000 1110 1101)_2 = A8B8ED$

Solving (d): To octal

$(i.)\ 74510$

Divide 74510 by 8 and keep track of the remainder

$74510/8\ |\ 9313\ R\ 6$

$9313/8\ |\ 1164\ R\ 1$

$1164/8\ |\ 145\ R\ 4$

$145/8\ |\ 18\ R\ 1$

$18/8\ |\ 2\ R\ 2$

$2/8\ |\ 0\ R\ 2$

Write out the remainder from bottom to top

$74510_8= 221416$

$(ii.)\ 67210$

Divide 67210 by 8 and keep track of the remainder

$67210/8\ |\ 8401\ R\ 2$

$8401/8\ |\ 1050\ R\ 1$

$1050/8\ |\ 131\ R\ 2$

$131/8\ |\ 16\ R\ 3$

$16/8\ |\ 2\ R\ 0$

$2/8\ |\ 0\ R\ 2$

Write out the remainder from bottom to top

$67210_8 = 203212$

8 0

3 years ago

Alison is having a hard time at work because her Inbox is flooded with emails every day. Some of these emails are unsolicited. S

rosijanka [135]

Answer:

(1) Spam, (2) Trash.

Explanation:

"Emails are unsolicited-" is another word for spam lol. And then "Others she doesn’t need." is, again, another word for trash. I mean if you don't need it is trash then.

WELP I hope I helped you even tho this is late. Ahem, well. Stay awesome!

8 0

3 years ago