If the tax rate is 8%, we need to find 108% of the price, or 330 times 1.08, which is $356.4
You basically plug in the x in the equation, for example if x = 4 and the equation is y = 2x + 5 you plug in 4 and the equation becomes y = 2(4) + 5. you then multiply and get y=8+5. from here u just add it and u get ur answer
The answer is 5 and associative property
Answer:
y + 5 > -2 i.e. option 4.
Step-by-step explanation:
An inequality is shown in the number line by an arrow and we have to identify the inequality from the options given.
It is clear from the given figure that the y variable is plotted and its value is greater than - 7 but not including - 7.
Therefore, option 4 which gives the inequality y + 5 > -2 will be the correct answer.
As it gives y > - 2 - 5 i.e. y > - 7 (Answer)
Let's take a look at the first few numbers in the sequence based on the given rule:

Inspecting this pattern it seems like the power

is being raised to is always one less than the number of the sequence, so if we were on the nth number in the sequence, that part of the expression would be

. We also know that we'll be multiplying whatever we get from that by 6, so we can write the full explicit rule for our sequence as

Where

is the nth number in our sequence.