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Andrew [12]
3 years ago
13

State whether the two triangles below are congruent? B А С Q S R

Mathematics
2 answers:
tamaranim1 [39]3 years ago
5 0

Answer:

Congruent

Step-by-step explanation:

There are 2 angles and a side that are congruent in both triangles. Therefore, they are congruent through AAS.

Viefleur [7K]3 years ago
4 0
The answer you need is congruent
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Solve for f. 2+1.25f=10-2.75f2+1.25f=10−2.75f
Ne4ueva [31]
We have to solve for f:
2 + 1.25 f = 10 - 2.75 f
1.25 f + 2.75 f = 10 + 2
4 f = 12
f = 12 : 4
f = 3
Answer: f = 3
6 0
4 years ago
Given: AB tangent to circle O at B, and secant through point A intersect the circle at points C and D. Find CD, if
azamat

Answer:

6 cm

Step-by-step explanation:

If you use Tangent-secant product (chapter reference), AB/AC = AD/AB so 4/2 = AD/4. AD = 8, CD = AD - AC = 8 - 2 = 6 cm.

3 0
3 years ago
Read 2 more answers
Somebody please help me with this !!!
Damm [24]

Step-by-step explanation:

Case 1 :

3x + 2y = 6 \\ 4x + y = 2 \\ 3x = 6 - 2y \\ x =  \frac{6 - 2y}{3}  = \\ x = 2 -  \frac{2y}{3}  \\ 4(2 -  \frac{2y}{3} ) + y = 2 \\ 8 -  \frac{8y}{3}  + y = 2 \\  - 1.67y =  - 6 \\

y = 3.59 \\ x = 2 -  \frac{2y}{3}  \\x =  2 -  \frac{2 \times 3.59}{3}  \\  \\ x =  - 0.39

Case 2 :

3x + 2y = 6 \\ 4x  -  y = 2 \\ x = 2 -  \frac{2y}{3}  \\ 4(2 -  \frac{2y}{3} ) - y = 2 \\ 8 -  \frac{8y}{3}  - y = 2 \\   - 3.67y=  - 6 \\ y = 1.63

x = 2 -  \frac{2y}{3}  \\ x = 2 -  \frac{2 \times 1.63}{3}  \\ x = 2 - 1.087 \\ x = 0.913

7 0
3 years ago
Why doesn’t inverse variation have no x and y intercept?
kirill115 [55]

Answer:

Since k is constant, we can find k given any point by multiplying the x-coordinate by the y-coordinate. For example, if y varies inversely as x, and x = 5 when y = 2, then the constant of variation is k = xy = 5(2) = 10. Thus, the equation describing this inverse variation is xy = 10 or y = .

I hope this was the answer u were looking for.

6 0
3 years ago
Help please! I’m giving brainliest to however gets this question right.
Arisa [49]

Answer:

They both have area 4

Step-by-step explanation:

Area of the square:

base*height = 2 * 2 = 4

Area of the triangle:

Using the left-side of the triangle as the base, and the height from the left-side to the bottom-right corner:

\frac{1}{2}base*height

\frac{1}{2}4\sqrt2*\sqrt2=4

We know the length of the diagonal is \sqrt2 as we are using a centimetre grid, so we can create an isosceles triangle with side lengths 1 and our unknown length, we can then use Pythagorean Theorem to work out our unknown side length.

a^2+b^2=c^2

1^2+1^2=c^2

2=c^2

\sqrt2=c

7 0
3 years ago
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