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Semenov [28]
2 years ago
14

15) Perry had some candy to give to his five

Mathematics
2 answers:
matrenka [14]2 years ago
6 0

Answer:

18

Step-by-step explanation:

let 'x' = pieces of candy at start

(x-3)/5 = 3

cross-multiply:

x - 3 = 15

x = 18

EleoNora [17]2 years ago
3 0

Answer:

18

Step-by-step explanation:

5 kids times 3 pieces each = 15 and then add the 3 that the dad got.

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A space shuttle is made
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Answer:

The actual space shuttle is 66 feet tall

Step-by-step explanation:

scale of 1 inch : 12 feet represent the scale of a space shuttle.

It means it has a representation of 1 inch on paper then actual = 12 feet.

But then if the paper(model) changes to 5.5 inches. The actual representation on land will be

Let me write out the equation

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A cube has side length of 2m. What is the surface area of the cube?
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Simplify the following without using a calculator<br>a)<br>- 4 x (8-(-3)) + 7​
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-4(8-(-3))+7

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3 years ago
A set of city temperatures in April are normally distributed with a mean of 19.7 degrees Celsius and a standard deviation of 2 d
Sati [7]

Answer:

19.77% of average city temperatures are higher than that of Cairo

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 19.7, \sigma = 2

What percentage of average city temperatures are higher than that of Cairo?

This is 1 subtracted by the pvalue of Z when X = 21.4.

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19.77% of average city temperatures are higher than that of Cairo

6 0
3 years ago
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