✿————✦————✿————✦————✿
The answer is: <u>2(k2−4k)(2c+5)</u>
✿————✦————✿————✦————✿
Step:
* Consider 2ck2+5k2−8ck−20k. Do the grouping 2ck2+5k2−8ck−20k=(2ck2+5k2) +(−8ck−20k), and factor out k2 in the first and −4k in the second group.
* Factor out the common term 2c+5 by using the distributive property.
* Rewrite the complete factored expression.
✿————✦————✿————✦————✿
Answer:
11.25
Step-by-step explanation:
15*(1-25%)=11.25
m<E=45.5 m<F=45.5
this is question 8 can't see question 9
Answer:
5.3
Step-by-step explanation:
Cos(68) = adjacent/hypotenuse
Cos(68) = 2/AC
AC = 2/cos(68)
AC = 5.3389343253
AC = 5.3
Answer:
See below.
Step-by-step explanation:
From the given info the 2 triangles are isosceles with AE = FR and ET = RP because the 2 sets of base angles are equal.
As the base angles are congruent m < E = m < R.
So the are 2 triangles are congruent by SAS, ASA and AAS.
