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pishuonlain [190]
3 years ago
15

16 football players need to raise 526.36 to buy football pads.They have already raised 278.51. If each player raises the same am

ount, how much more money must each student raise
Mathematics
1 answer:
malfutka [58]3 years ago
5 0
Subtract the money they already raised from the money they needed to raise
That gives you $247.85
247.85/16 = 15.490625
That estimates to $15.49
Hope this helps! :)
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Mhanifa u helped me with this question.... U said it was 25 and its not so why is it wrong
Yanka [14]

Hey I don't know who Mhanifa is but 25 is correct, and I will put the entire explanation to how to get the answer here.

First of all the 2 lines on the left and right side of the triangles are means that those 2 lines are equal and thus forming a isosceles triangle.

This means that the bottom right angle is also 2x+2 degrees.

Now because all 3 angles in a triangle adds to 180 degrees, we can set up equation.

3x+1+2x+2+2x+2=180

Now combine like terms

7x+5=180

Then solve, first subtract 5 from both sides.

7x=175

Now divide 7 from both sides

x=25

6 0
3 years ago
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Charles has $20 to spend at the bakery he wants to buy six cupcakes and a pie. The pie costs
Oduvanchick [21]
The most he can buy for each cupcake is 1.25
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3 years ago
Find the slope and y-intercept of line x÷a+y÷b=1​
Inessa05 [86]

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y-intercept:

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6 0
2 years ago
The exterior walls and roof of a barn are to be painted. The barn is in the shape of a rectangular prism, with an isosceles tria
vlada-n [284]

<u>Given:</u>

The rectangular prism has a length of 25 feet, a width of 10 feet and a height 55 feet.

The triangular prism has a base length of 25 feet, a height of 8 feet, and a prism height of 55 feet.

<u>To find:</u>

The total area to be painted.

<u>Solution:</u>

There are 4 external surfaces for the rectangular prism and 4 external surfaces for the triangular prism.

The rectangular prism has 4 rectangles out which there are 2 sets of similar rectangles.

There are two rectangles with lengths of 25 feet and widths of 10 feet while the other two rectangles have lengths of 55 feet and widths of 10 feet.

The area of a rectangle with a length of 25 feet and a width of 10 feet = 25(10)= 250 square ft.

The area of two such rectangles = 2(250) = 500 square feet.

The area of a rectangle with a length of 55 feet and a width of 10 feet = 55(10)= 550 square feet.

The area of two such rectangles = 2(550) = 1100 square feet.

The triangular prism has 2 triangles and 2 rectangles.

The triangles have base lengths of 25 feet and heights of 8 feet while the rectangles have lengths of 55 feet and heights of 14.8 feet.

The area of a triangle with a base length of 25 feet and a height of 8 feet = \frac{1}{2}(25)(8)= 100 square feet.

The area of two such triangles =2(100)= 200 square feet.

The area of a rectangle with a length of 55 feet and a width of 14.8 feet = 55(14.8)= 814 square feet.

The area of two such rectangles = 2(814) = 1628 square feet.

The total area to be painted =500+1100+200+1628 = 3128 square feet.

So an area of 3128 square feet is to be painted.

8 0
3 years ago
Whoever can solve this prob will get a very special reward! Math prob: Put parentheses on 3 + 6 x 5 divided by 2 - 7 to make the
liraira [26]

Answer:

(3+6*5)/2-7

Step-by-step explanation:

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3 years ago
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