Answer:
The rate at which the distance between the two cars is increasing is 30 mi/h
Step-by-step explanation:
Given;
speed of the first car, v₁ = 24 mi/h
speed of the second car, v₂ = 18 mi/h
Two hours later, the position of the cars is calculated as;
position of the first car, d₁ = 24 mi/h x 2 h = 48 mi
position of the second car, d₂ = 18 mi/h x 2 h = 36 mi
The displacement of the two car is calculated as;
displacement, d² = 48² + 36²
d² = 3600
d = √3600
d = 60 mi
The rate at which this displacement is changing = (60 mi) / (2h)
= 30 mi/h
U got 22 riders....each has 1 saddle....so u got 22 saddles...each saddle has 2 saddle bags....so u have 22(2) = 44 saddle bags...each saddle bag has 3 water bottles....so 44(3) = 132 water bottles
Answer:
12-10=2
2 parts of 10 is 20 percent.
The rate went up 20%.
Step-by-step explanation:
Simplify 1/125
1/125 . (x3))-1) ÷ 3
(x3
(———)-1) ÷ 3
125
3.1 x3 raised to the minus 1 st power = x( 3 * -1 ) = x-3
3.2 125 = 53 (125)-1 = (53)(-1) = (5)(-3)
x(-3)
——————— ÷ 3
(5)(-3)
x(-3)
Divide ——————— by 3
(5)(-3)
Answer: 125
/3x3
