Let thw second integer be x
then the first = 2x
and the third integer is = 6+x
their sum = 74
x+2x+6+x = 74
4x +6 = 74
4x = 74-6 =68
x =68÷4
x = 17
then the first integer is 2×17 = 34
the third integer is 17+6 = 23
the integers are 17 , 23 and 34
Answer:
Shira: x = 8
Samuel: m = 0
Step-by-step explanation:
Shira's mistake was that she subtracted 2 from both sides instead of adding to on both sides.
Correct Solving:
2x - 2 = 14
Add 2 to both sides;
2x = 16
Divide both sides by 2;
x = 8
Samuel's mistake was that when he distributed -2 to 8m and 8 he put the wrong sign for -2 * 8.
Correct Solving:
-2(8m + 8) = -16
Distribute;
-16m - 16 = -16
Add 16 to both sides;
-16m = 0
Divide both sides by -16;
m = 0
Factors of 18: 1; 2; 3; 6; 9; 18
Factors of 27: 1; 3; 9; 27
GCF(18; 27) = 9
<span>18 + 27 = 9 × 2 + 9 × 3 = 9 × (2 + 3) </span>
