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3 years ago

Rule: y=x+3 HELPpppppp

Mathematics

2 answers:

dimaraw [331]3 years ago

7 0

Answer:

Step-by-step explanation:

when y=4

x=4-3=1

when y=8

x=8-3=5

when y=5

x=5-3=2

aivan3 [116]3 years ago

4 0

Answer:

$\left[\begin{array}{ccc}x&y\\1&4\\5&8\\2&5\end{array}\right]$

Step-by-step explanation:

x + 3 = y

1 + 3 = 4

5 + 3 = 8

2 + 3 = 5

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For questions 3 - 5, answer the questions about the equations.

mrs_skeptik [129]

Answer:

infinite solutions

Step-by-step explanation:

Eliminate parentheses and collect terms:

3x -12 +5 -x = 2x -7

2x -7 = 2x -7

This is true for any value of x. There are an infinite number of solutions.

6 0

3 years ago

What are the lower and upper quartiles of this data 122,164,71,98,84,147,114,111,98,85,104,71,77

RSB [31]

Lower quartile = 80.5
Upper quartile = 118

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2 years ago

Follow the process of completing the square to solve 2x2 + 8x - 12 = 0.

Rom4ik [11]

Please: Use "^" to denote exponentiation: 2x^2 + 8x - 12 = 0

Reduce this by div. every term by 2: x^2 + 4x - 6 = 0

Here a=1, b=4 and c = -6. Square half of b, obtaining (4/2)^2 = 4, and add, and then subtract, this 4 to x^2 + 4x - 6:

 x^2 + 4x +4 - 4 - 6 = 0. Rewrite the square as (x+2)^2, obtaining new equation

(x+2)^2 = 10. Take the sqrt of both sides: x+2 = plus or minus sqrt(10).

Finally, solve for x: x = -2 plus or minus sqrt(10).

8 0

3 years ago

A cone and a triangular pyramid have a height of 9.3 m

Otrada [13]

Answer:

$x=17.1\ in$

Step-by-step explanation:

The complete question is

A cone and a triangular pyramid have a height of 9.3 m and their cross-sectional areas are equal at every level parallel to their respective bases. The radius of the base of the cone is 3 in and the other leg (not x) of the triangle base of the triangular pyramid is 3.3 in

What is the height, x, of the triangle base of the pyramid? Round to the nearest tenth

The picture of the question in the attached figure

we know that

If their cross-sectional areas are equal at every level parallel to their respective bases and the height is the same, then their volumes are equal

Equate the volume of the cone and the volume of the triangular pyramid

$\frac{1}{3}\pi r^{2}H=\frac{1}{3}[\frac{1}{2}(b)(h)H]$