Answer:
A. elements of the same kind with different numbers of neutrons
Explanation:
As we know that an atom is represented by
![_z^AX](https://tex.z-dn.net/?f=_z%5EAX)
here we know that
z = atomic number
A = atomic number + number of neutrons
now if the number of neutrons in an atom is different but having same number atomic number then the combination of such group of atoms is known as isotopes.
So here we have
![_z^{A_1}X, _z^{A_2}X](https://tex.z-dn.net/?f=_z%5E%7BA_1%7DX%2C%20_z%5E%7BA_2%7DX)
so above is the example of isotopes
Explanation:
For each point:
PE = mgh
KE = ½ mv²
ME = PE + KE
Since energy is conserved, ME will be constant.
I'll be using g = 10 m/s².
A. PE = (100 kg) (10 m/s²) (102 m) = 102,000 J
KE = ½ (100 kg) (0 m/s)² = 0 J
ME = 102,000 J
B. KE = ½ mv²
18,000 J = ½ (100 kg) v²
v = 60 m/s
ME = 102,000 J
PE = ME − KE = 84,000 J
(100 kg) (10 m/s²) h = 84,000 J
h = 84 m
C. KE = ½ (100 kg) (29 m/s)² = 42,050 J
ME = 102,000 J
PE = ME − KE = 59950 J
(100 kg) (10 m/s²) h = 59950 J
h = 59.95 m
d. PE = (100 kg) (10 m/s²) (60 m) = 60,000 J
ME = 102,000 J
KE = ME − PE = 42,000 J
½ (100 kg) v² = 42,000 J
v = 29.0 m/s
E. PE = (100 kg) (10 m/s²) (0 m) = 0 J
ME = 102,000 J
KE = ME − PE = 102,000 J
½ (100 kg) v² = 102,000 J
v = 45.2 m/s
Mechanical waves require medium
the weight of the space probe on that planet is 50 N
To calculate the weight of the space probe, we use the formula below.
Formula:
Where:
- W = weight of the space probe on the planet
- m = mass of the space probe
- g = acceleration due to gravity.
From the question,
Given:
Substitute these values into equation 1
Hence, the weight of the space probe on that planet is 50 N
Learn more about weight here: brainly.com/question/229459
The point in the orbit of a planet, asteroid, or comet at which it is closest to the sun.