Answer:
0.6 C
Explanation:
From the question,
Since the Resistor and the capacitor are connected in series.
The voltage across the resistor + Voltage across the capacitor = Total voltage.
Vt = Vr+Vc............... Equation 1
Where Vt = Total voltage, Vr = Voltage across the resistor, Vc = Voltage across the capacitor
make Vc the subject of the equation
Vc = Vt-Vr.............. Equation 2
From ohm's law,
Vr = IR................... equation 3
Where I = current, R = Resistance.
Given: I = 1 A, R = 50 Ω
Substitute into equation 3
Vr = 1(50)
Vr = 50 V
Also given: Vt = 200 V
Substitute into equation 2
Vc = 200-50
Vc = 150 V.
Applying,
Q = CVc..................... Equation 4
Where Q = charge on each plate of the capacitor, C = Capacitance of the capacitor
Given: C = 4.0 mF = 4.0×10⁻³ F, Vc = 150 V
Substitute into equation 4
Q = 4.0×10⁻³(150)
Q = 0.6 C
