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3 years ago

7

Mark's uncle is about to have a procedure to treat his prostate cancer. The treatment involves placement of small pellets close

to the tumor to deliver a localized dose of radiation. What type of nuclear therapy is this?

1 answer:

Rus_ich [418]3 years ago

7 0

Answer: brachytherapy

Explanation:

Just answered it right

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An astronaut stands on the surface of an asteroid. The astronaut then jumps such that the astronaut is no longer in contact with

Anna71 [15]

(D) The gravitational force between the astronaut and the asteroid.

Reason :

All the other forces given in the options, except (D), doesn't account for the motion of the astronaut. They are the forces that act between nucleons or atoms and neither of them accounts for an objects motion.

6 0

3 years ago

The suspension system of a 1700 kg automobile "sags" 7.7 cm when the chassis is placed on it. Also, the oscillation amplitude de

spin [16.1K]

Answer:

the spring constant k = $5.409*10^4 \ N/m$

the value for the damping constant $\\ \\b = 1.518 *10^3 \ kg/s$

Explanation:

From Hooke's Law

$F = kx\\\\k =\frac{F}{x}\\\\where \ F = mg\\\\k = \frac{mg}{x}\\\\given \ that:\\\\mass \ of \ each \ wheel = 425 \ kg\\\\x = 7.7cm = 0.077 m\\\\g = 9.8 \ m/s^2\\\\Then;\\\\k = \frac{425 \ kg * 9.8 \ m/s^2}{0.077 \ m}\\\\k = 5.409*10^4 \ N/m$

Thus; the spring constant k = $5.409*10^4 \ N/m$

The amplitude is decreasing 37% during one period of the motion

$e^{\frac{-bT}{2m}}= \frac{37}{100}\\\\e^{\frac{-bT}{2m}}= 0.37\\\\\frac{-bT}{2m} = In(0.37)\\\\\frac{-bT}{2m} = -0.9943\\\\b = \frac{2m(0.9943)}{T}\\\\b = \frac{2m(0.9943)}{\frac{2 \pi}{\omega}}\\\\b = \frac{m(0.9943) \ ( \omega) )}{ \pi}$

$b = \frac{m(0.9943)(\sqrt{\frac{k}{m})}}{\pi}\\\\b = \frac{425*(0.9943)(\sqrt{\frac{5.409*10^4}{425}) } }{3.14}\\\\b = 1518.24 \ kg/s\\\\b = 1.518 *10^3 \ kg/s$

Therefore; the value for the damping constant $\\ \\b = 1.518 *10^3 \ kg/s$

5 0

3 years ago

A Net Force of 9.0 N acts through a distance of 3.0 m in a time of 3.0 s. The work done is?

JulijaS [17]

Work done is the distance a force acts over.

So, the work done here is 9.0N * 3.0m = 27 J

5 0

3 years ago

Read 2 more answers

In a lab, the mass of object A is 2.5 kg. Object A weighs:

dangina [55]

Answer:

25N

Explanation:

Assuming the lab is on earth:

w = mg = 2.5 (9.81) = 25N

8 0

3 years ago

A soccer ball moving with an initial speed of 1.8 m/s is kicked with a

vova2212 [387]

Answer:

7.0 m

Explanation:

Step 1: Given data

Initial speed of the ball (u): 1.8 m/s

Acceleration (a): 6.1 m/s²

Final speed of the ball (v): 9.4 m/s

Step 2: Calculate the displacement (s) of the ball

The ball is moving with a uniformly accelerated rectilinear motion. We can calculate the displacement using the following suvat equation.

v² = u² + 2 × a × s

s = (v² - u²)/2 × a

s = [(9.4 m/s)² - (1.8 m/s)²]/2 × 6.1 m/s²

s = 7.0 m

7 0

2 years ago