Answer:
(b) The interquartile range of B is greater than the interquartile range of A.
(d) The median of A is the same as the median of B.
Explanation:
Given


So:

Required
Select all true statements
(a) & (d) Median Comparisons


Arrange the data:




--- average of 5th and 6th

Option (d) is correct because both have a median of: 2
(b) & (c) Interquartile Range Comparisons


First, calculate the lower quartile (Q1)
[Odd n]
[Even n]


This means that:


Next, calculate the upper quartile (Q3)
[Odd n]
[Even n]

This means that:

The interquartile range is 
So, we have:


(b) is true because B has a greater IQR than A
(e) This is false because some spread measures (which include quartiles and the interquartile range) changed when the 10th data is included.
The upper quartile and the interquartile range of A and B are not equal
Gravity is one reason but also it depends in the speed, if the wave is fast, it will go higher and then bend. hope i helped :D
Answer:
The template DNA strand, from which the mRNA is synthesized, is 5' ... so the template strand and the mRNA will be complementary to each other) ... ATG Met (M) ... The following codons can be mutated by one base to produce an amber codon: ... which amino acid should be incorporated in the growing polypeptide chain.
Explanation:
Answer:
Microbiological contamination refers to the non-intended or accidental introduction of infectious material like bacteria, yeast, mould, fungi, virus, prions, protozoa or their toxins and by-products. 1,2
Explanation:
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Use binomial distribution with p=0.25, n=5, x=2
P(X=x)=C(n,x)p^x (1-p)^(n-x)
P(X=2)=C(5,2) 0.25^2 0.75^(5-2)
=10*0.0625*0.421875
=0.26367
So the probability of 2 of 5 children having type-O blood from these parents is 0.26367.