Angle A = 3x - 10
Angle B = x
Their angle sum = 90° ( complementary angles form 90° )
This can be written in an equation as =
= 3x - 10 + x = 90
= 3x + × + ( -10 ) = 90
= 4x + (-10) = 90
= 4x = 90 + 10 ( transposing-10 from LHS to RHS changes-10 to +10 )
= 4x = 100
= x = 100 ÷ 4 ( transposing ×4 from LHS to RHS changes ×4 to ÷4 )
= x = 25
Angle A = 3x - 10
= 3 × 25 - 10
= 75 - 10
= Angle A = 65°
Angle B = x = 25°
Their sum = 65 + 25 = 90°
Therefore , the complementary angles , Angle A = 65° and Angle B = 25° .
V of rectangular prism = l * w * h = 12 * 2 * 312 = 7,488 in³
V of one cube with side lengths 12 = l * w * h = 12 * 12 * 12 = 1,728 in³
Divide the volume of rectangular prism by the volume of the cube.
7488 / 1728 = 13 / 3 or 4.3. . .
Answer:
z(s) is in the rejection region. We reject H₀. We dont have enought evidence to support that the cream has effect over the recovery time
Step-by-step explanation:
Sample information:
Size n = 100
mean x = 28,5
Population information
μ₀ = 30
Standard deviation σ = 8
Test Hypothesis
Null Hypothesis H₀ x = μ₀
Alternative Hypothesis Hₐ x < μ₀
We assume CI = 95 % then α = 5 % α = 0,05
As the alternative hypothesis suggest we should develop a one tail-test on the left ( we need to find out if the cream have any effect on the rash), effects on the rash could be measured as days of recovery
A z(c) for 0,05 from z-table is: z(c) = - 1,64
z(s) = ( x - μ₀ ) / σ/√n
z(s) = ( 28,5 - 30 ) / 8/√100
z(s) = - 1,5 * 10 / 8
z(s) = - 1,875
Comparing z(s) and z(c)
|z(s)| < |z(c)| 1,875 > 1,64
z(s) is in the rejection region. We reject H₀. We dont have enought evidence to support that the cream has effect over the recovery time
Answer:
$41
Step-by-step explanation:
- One room rents for $68,
- Two rooms for $65 each,
- In general, the group rate per room is found by taking $3 off the base of $68 for each extra room.
So,
where 
is the rate per nth room rented.
This is an arithmetic sequence, so
In your case,
Hence
This means if a group rents 10 rooms, the charge per room is $41.
Answer:
You are given:
4Fe+3O_2 -> 2Fe_2O_3
4:Fe:4
6:O_2:6
You actually have the same number of Fe on both sides, The same is true for O_2 so yes this equation is properly balanced.
For added benefit consider the following equation:
CH_4+O_2-> CO_2+2H_2O
ASK: Is this equation balanced? Quick answer: No
ASK: So how do we know and how do we then balance it?
DO: Count the number of each atom type you have on each side of the equation:
1:C:1
4:H:4
2:O:4
As you can see everything is balanced except for O To balance O we can simply add a coefficient of 2 in front of O_2 on the left side which would result in 4 O atoms:
CH_4+color(red)(2)O_2-> CO_2+2H_2O
1:C:1
4:H:4
4:O:4
Everything is now balanced.
Step-by-step explanation:
