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Lady bird [3.3K]
3 years ago
12

If Emily had 97 apples and needs to know how many bags to put them into. How many bags will she need

Mathematics
1 answer:
Galina-37 [17]3 years ago
4 0

Answer:

12?

Step-by-step explanation:

97/8=12.125

You might be interested in
Simplify each expression.<br><br> 5x+ 3/4 +2x− 1/2
suter [353]

Answer:

7x+1/4

Step-by-step explanation:

5x+3/4+2x+-1/2

Combine Like Terms:

5x+3/4+2x+-1/2

(5x+2x)+(3/4+-1/2)

7x+1/4

Hope this helps

7 0
2 years ago
alyssa has 6 quarters, 4 dimes and 5 nickels in her change jar. if she picks 2 at random, what is the probability that she will
rusak2 [61]
The probability of Alyssa picking a nickel and a quarter would be 11/15 (eleven over fifteen)

6/15 plus 5/15 which is 11/15
You get 15 as the denominator because you add 6+4+5=15

I hope u understand.
5 0
3 years ago
A store sells a 33-pound bag of oranges for \$ 3.60$3.60 and a 55-pound bag of oranges for \$ 5.25$5.25. What is the difference
katrin [286]

Answer:

0.01364

Step-by-step explanation:

It is given that,

A store sells a 33-pound bag of oranges for $3.60 and a 55-pound bag of oranges for $5.25.

Price per pound of 33 pound bag is 3.60/33 = 0.10909 price per pound

Price per pound of 55 pound bag of oranges is 5.25/55 = 0.09545 price per pound

Difference between price per pound for the 33-pound bag of oranges and the price per pound for the 55-pound bag of oranges is :

D = 0.10909 - 0.09545

D = 0.01364

Therefore, this is the required solution.

3 0
3 years ago
One number is three more than a second number. Three times the first is 13 less than 5 times the second.
irakobra [83]

14 and 11

let x be the second number then the first number = x + 3 ( 3 more than second)

Also 3(x + 3) = 5x - 13

3x + 9 = 5x - 13

subtract 3x from both sides

9 = 5x - 3x - 13

9 = 2x - 13

add 13 to both sides

22 = 2x

divide both sides by 2

11 = x → second number

first number = x + 3 = 11 + 3 = 14


6 0
3 years ago
I don’t understand this help please
Elodia [21]

Answer:

  9

Step-by-step explanation:

The first simplification we can make is to replace 6^0 with 1.

The first rules of exponents we can apply are ...

  <em>(a·b)^c = a^c·b^c</em> . . . . . . similar to the distributive property

<em>   (a^b)^c = a^(b·c)</em>

This reduces your expression to ...

  (2^8\cdot 3^{-5})^{-2}\cdot\left(\dfrac{3^{-2}}{2^3}\right)^4\cdot 2^{28}=2^{8(-2)}\cdot 3^{-5(-2)}\cdot\dfrac{3^{-2(4)}}{2^{3(4)}}\cdot 2^{28}\\\\=2^{-16}\cdot 3^{10}\cdot\dfrac{3^{-8}}{2^{12}}\cdot 2^{28}

Now we can apply another two rules of exponents:

<em>   (a^b)(a^c) = a^(b+c)</em>

<em>   1/a^b = a^-b</em>

Using these, we have ...

  =2^{-16-12+28}\cdot 3^{10-8}\\\\=2^0\cdot 3^2\\\\=1\cdot 9=9

The value of the expression is 9.

3 0
3 years ago
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