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Tresset [83]
3 years ago
12

PLEASEE HELP ME!!!!!!!!!!!

Mathematics
1 answer:
zavuch27 [327]3 years ago
4 0

Answer:

26%

Step-by-step explanation:

13/50=0.26

0.26x100=26%

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An 8 oz glass of grape juice contains 0.6 mg of iron. About what percent of RDA of iron for an 15 year old male is provided by 8
babymother [125]

Answer:

5.45%


Step-by-step explanation:

To find info of a 15 year old male, you look at the Age Group of 14 - 18, beside Male.

The RDA of Iron is given as 11 mg

From a 8 oz glass of grape juice, he gets 0.6 mg.


<em>What percent is 0.6 mg of total 11 mg??</em>


Divide 0.6 by 11 and then multiply by 100 to get the answer. So we have:

\frac{0.6}{11}=0.0545*100=5.45

Thus, 5.45% of RDA of iron is provided by an 8 oz glass of grape juice.

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3 years ago
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Natasha2012 [34]

Answer:

56.55

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2*3.14*9^2

8 0
3 years ago
Find the Maclaurin series for f(x) using the definition of a Maclaurin series. [Assume that f has a power series expansion. Do n
aliya0001 [1]

Answer:

f(x)=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}

Step-by-step explanation:

The Maclaurin series of a function f(x) is the Taylor series of the function of the series around zero which is given by

f(x)=f(0)+f^{\prime}(0)x+f^{\prime \prime}(0)\dfrac{x^2}{2!}+ ...+f^{(n)}(0)\dfrac{x^n}{n!}+...

We first compute the n-th derivative of f(x)=\ln(1+2x), note that

f^{\prime}(x)= 2 \cdot (1+2x)^{-1}\\f^{\prime \prime}(x)= 2^2\cdot (-1) \cdot (1+2x)^{-2}\\f^{\prime \prime}(x)= 2^3\cdot (-1)^2\cdot 2 \cdot (1+2x)^{-3}\\...\\\\f^{n}(x)= 2^n\cdot (-1)^{(n-1)}\cdot (n-1)! \cdot (1+2x)^{-n}\\

Now, if we compute the n-th derivative at 0 we get

f(0)=\ln(1+2\cdot 0)=\ln(1)=0\\\\f^{\prime}(0)=2 \cdot 1 =2\\\\f^{(2)}(0)=2^{2}\cdot(-1)\\\\f^{(3)}(0)=2^{3}\cdot (-1)^2\cdot 2\\\\...\\\\f^{(n)}(0)=2^n\cdot(-1)^{(n-1)}\cdot (n-1)!

and so the Maclaurin series for f(x)=ln(1+2x) is given by

f(x)=0+2x-2^2\dfrac{x^2}{2!}+2^3\cdot 2! \dfrac{x^3}{3!}+...+(-1)^{(n-1)}(n-1)!\cdot 2^n\dfrac{x^n}{n!}+...\\\\= 0 + 2x -2^2  \dfrac{x^2}{2!}+2^3\dfrac{x^3}{3!}+...+(-1)^{(n-1)}2^{n}\dfrac{x^n}{n}+...\\\\=\sum_{n=1}^{\infty}(-1)^{(n-1)}2^n\dfrac{x^n}{n}

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3 years ago
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The length of the lake trail is 1.0miles
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