Step-by-step explanation:
<h2>
MN=x+16</h2><h2>
MN=x+16LN=4x+16</h2><h2>
MN=x+16LN=4x+16LM+MN=LN</h2><h2>
MN=x+16LN=4x+16LM+MN=LNLM+(x+16)=4x+16</h2><h2>
MN=x+16LN=4x+16LM+MN=LNLM+(x+16)=4x+16LM=(4x+16)-(x+16)</h2><h2>
MN=x+16LN=4x+16LM+MN=LNLM+(x+16)=4x+16LM=(4x+16)-(x+16)LM=4x+16-x-16</h2><h2>
MN=x+16LN=4x+16LM+MN=LNLM+(x+16)=4x+16LM=(4x+16)-(x+16)LM=4x+16-x-16LM=3x</h2><h2>
MN=x+16LN=4x+16LM+MN=LNLM+(x+16)=4x+16LM=(4x+16)-(x+16)LM=4x+16-x-16LM=3x </h2><h2>
MN=x+16LN=4x+16LM+MN=LNLM+(x+16)=4x+16LM=(4x+16)-(x+16)LM=4x+16-x-16LM=3x 3x=x+16 3x-x=16 2x=16 x=16/2 x=8 MN=x+16=8+16=24</h2>
Answer:
C. t > 40
Step-by-step explanation:
Answer:
75
Step-by-step explanation:
Simplify the following:
-6 - 7 (-4) + 5 - 8×(-9)/(-3) (-2)
-8×(-9)/(-3) (-2) = (-8 (-9) (-2))/(-3):
-6 - 7 (-4) + 5 + (-8 (-9) (-2))/(-3)
(-9)/(-3) = (-3×3)/(-3) = 3:
-6 - 7 (-4) + 5 - 83 (-2)
-7 (-4) = 28:
-6 + 28 + 5 - 8×3 (-2)
-8×3 = -24:
-6 + 28 + 5 + -24 (-2)
-24 (-2) = 48:
-6 + 28 + 5 + 48
| 2 |
| 4 | 8
| 2 | 8
+ | | 5
| 8 | 1:
81 - 6
| 7 | 11
| 8 | 1
- | | 6
| 7 | 5:
Answer: 75
There is a 60 minute gap between the two clocks.
These 60 minutes result of a 1 min advance in one for each hour and a 2 min loss in the other.
if we are going 2 mins back and 1 min in
We have a 3 min gap/hour
then to reach a 1 hour gap we would need to go for 2+1+2+1+2+1+2....(20 hours)
since each 3 represent an hour,
to get 60 min gap>60/3=20 hours
Take clock 1 for example, which read 12:00, in reality the time is (12:00-20 minutes)=11:40
or
Take clock 2 for example, which read 11:00, in reality the time is (11:00+20×2 minutes)=11:40
Now go back 20 hours from that;
11:40-20=00:40-9=15:40
There's ur answer 15:40 :)