A and b are legs
a^2+b^2=c^2
lets say
a>b
so
a=13+3b
c=14+3b
a^2+b^2=c^2
(13+3b)^2+b^2=(14+3b)^2
9b^2+78b+169+b^2=9b^2+84b+196
10b^2+78b+169=9b^2+84b+196
minus 9b^2 both sides
b^2+78b+169=84b+196
minus 84b both sides
b^2-6b+169=196
minus 196 both sides
b^2-6b-27=0
factor
(b+3)(b-9)=0
set to zero
b+3=0
b=-3, false, dimentions cannot be negative
b-9=0
b=9
shorter leg is 9
a=13+3b
a=13+3(9)
a=13+27
a=40
c=14+3b
c=14+27
c=41
side legnths are
9in, 40in, 41in
3(2)+17-28
multiply 3(2)=6
6+17-28
work left to right
6+17=23
23-28=-5
Answer:
B
Step-by-step explanation:
Divide 35 by 6 and get 36. Take away from the answer until you get the bigger number in it and there y go.
Saying "4 ft, 2 inches" is the same as saying "4 feet plus 2 inches"
1 foot = 12 inches
4 feet = 48 inches (multiply both sides by 4)
4 feet, 2 inches = 4 ft + 2 in
4 ft, 2 in = 48 in + 2 in
4 ft, 2 in = 50 in
The expression "4 ft, 2 inches" is the same as "50 inches"
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Now we can subtract off 14 inches from this
50 - 14 = 36
We're left with 36 inches which converts to 3 feet because
36/12 = 3
or you can think of it like this
1 ft = 12 in
3 ft = 36 in (multiply both sides by 3)
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<h3>Answer: 3 feet</h3>
15.8 because you round up from the .78 to .8
