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3 years ago

8

you have four chains of three links each. although it is difficult to cut the links, you wish to make a single loop with all 12

links. what is the fewest numbers of cuts you must make to accomplish this task

1 answer:

mel-nik [20]3 years ago

3 0

You have 4 parts that you want to combine so you need to make 3 cuts

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(Y^2-y+5)/(y+1)<br><br> Can someone please help me

Papessa [141]

Y - 2 + $\frac{7}{y + 1}$

Your teacher may also just want the answer y - 2 with a 7 remainder

Either way, you set it up like long division and solve as such.

8 0

3 years ago

Suppose that an individual has a body fat percentage of 14.5% and weighs 167 pounds. How many pounds of her weight is made up of

fenix001 [56]

167 divided by 100 = 1.67
1.67 x 14.5= 24.215
answer to nearest tenth = 24.2

3 0

3 years ago

Read 2 more answers

PLS I NEED HELP NOW PRONTO!!!!!

weeeeeb [17]

Answer:

The mean for Stem is 2.5

The mean for Leaf is 81.25

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2 years ago

D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x

MA_775_DIABLO [31]

The solution depends on the value of $k$ . To make things simple, assume $k>0$ . The homogeneous part of the equation is

$\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0$

and has characteristic equation

$r^2-16k=0\implies r=\pm4\sqrt k$

which admits the characteristic solution $y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}$ .

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be $y_p=ae^{4x}+be^x$ . Then

$\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x$

So you have

$16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x$
$(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x$

This means

$16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}$
$b(1-16k)=30\implies b=\dfrac{30}{1-16k}$

and so the general solution would be

$y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x$

8 0

3 years ago

Are the triangles congruent if they are which theorem and why?

leonid [27]

Yes the sides are equal to each other

7 0

3 years ago