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2 years ago

Describe the translation below using words and then write a rule for it.

Mathematics

1 answer:

Triss [41]2 years ago

7 0

The transformation of the figure is a translation. The original figure moves over 2 squares, then down once. The rule would be (x-2, y-1)

I’m pretty sure the answer is correct but my wording may not be so good :|

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Find The surface area of the cylinder. round your answer to the nearest tenth

trasher [3.6K]

Answer:

791.7

.......

........................

6 0

2 years ago

I NEED HELP ASAP PLEASE!!!

Artemon [7]

Answer:

-3x+1y=-1

3x-1y=1

by multiplying with 1/3 the first equation we get

-1x+1/3y=-1/3

or from second equation

1x-1/3y=1/3

Step-by-step explanation:

y-y1=m(x-x1)

y1=-7

x1=-2

m=3

y-(-7)=3(x-(-2))

y+7=3(x+2)

y+7=3x+6

-3x+y=6-7

-3x+ 1y= -1

8 0

2 years ago

Write the ratio as a fraction in simplest form.

vitfil [10]

Answer:

Part 1) $\frac{5}{2}$ or $5:2$

Part 2) $\frac{8}{1}$ or $8:1$

Step-by-step explanation:

Write the ratio as a fraction in simplest form

Part 1) 15 girls to 6 boys

we know that

To find out the ratio, divide the number of girls by the number of boys

$\frac{15}{6}$

Simplify

Divide by 3 both numerator and denominator

$\frac{5}{2}\ \frac{girls}{boys}$

Part 2) 24 plays for 3 teams

we know that

To find out the ratio, divide the number of plays by the number of teams

$\frac{24}{3}$

Simplify

Divide by 3 both numerator and denominator

$\frac{8}{1}\ \frac{plays}{team}$

5 0

3 years ago

Hhjjrrkhgcgvhvhgccffiigojjsttuupid

Anna71 [15]

well im not sure this can ne answered buddy

4 0

3 years ago

Paul plays a video game that is scored by round . In about 500 rounds his career average is 20 points per round with a standard

DanielleElmas [232]

Answer:

The mean of the sampling distribution is 20 and the standard deviation is 2.89.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Population:

Mean 20, standard deviation of 5.

Sampling distribution:

3 rounds

Mean = 20

$s = \frac{5}{\sqrt{3}} = 2.89$

The mean of the sampling distribution is 20 and the standard deviation is 2.89.

5 0

3 years ago