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Bezzdna [24]
3 years ago
12

Answer the question please: The correct answer will be marked as brainliest =) thanks xoxo

Mathematics
2 answers:
Mumz [18]3 years ago
6 0
When there is multiplication, we add the powers.. But when there is division, we subtract the powers. Therefore:

3^8 x 3^4 is 3^8+4= 3^12 (this is the numerator)

3^2x3^8 is 3^ 2+8= 3^10 (this is the denominator)

Now since there is a division bar we obviously have to divide the numerator: 3^12 by the denominator: 3^10. [Remember division requires subtraction of powers] therefore:
3^12 \ 3^10 = 3^12-10
= 3^2. (=9)
And is not given as 9 since it is not in index form therefor answer is 3 power of 2 (3^2)
Hope this is helpful for you!
Jlenok [28]3 years ago
3 0

Answer:

<h2>9</h2>

Step-by-step explanation:

Just multiply the numerator together using a calculator (for ease) then multiply the denominators including the powers. Once you did this part properly you should get,

531441/59049

= 9

You might be interested in
A manager of a grocery store wants to determine if consumers are spending
ololo11 [35]

Answer:

1. The error in the assumption is taking the sample mean, \bar x, as being equal to the population mean, μ

2. To correct the error, the manager will need to generate the confidence interval based on the population standard deviation on the acceptable values of the mean using the following relation;

CI=\bar{x}\pm z\frac{\sigma}{\sqrt{n}}

Step-by-step explanation:

We note that from the central limit theorem as the size of the sample, n, becomes more and more larger, the mean of the sample, \bar x, approaches that of the population mean, μ, therefore as the grocery store manager uses the sample mean as the population mean's point estimate an error will be observed based on the size of the sample compared to the population, where the difference between the two means (the population mean and the sample mean) is \left | \bar{x} - \mu \right |

1. The error in the assumption is taking the sample mean, \bar x, as being equal to the population mean, μ

2. To correct the error, the manager will need to generate the confidence interval based on the population standard deviation on the acceptable values of the mean using the following relation;

CI=\bar{x}\pm z\frac{\sigma}{\sqrt{n}}

Where:

σ = Population standard deviation = $30

z = z value at 95% confidence level = 1.96

\bar x = Sample mean $160

n = Sample size = 10

Plugging in the values, we have;

$141.4 < \bar x < $178.6

Hence the expected value of the mean should be between $141.4 and $178.6.

7 0
3 years ago
A comic book costs $3.99, including tax. It is marked up 45%.
nalin [4]
10% of 3.99=0.399x4=1.596
1% of 3.99=0.0399x5=0.1995
1.596+0.1995=1.7955
1.8(Rounded)+3.99=5.79
7 0
3 years ago
Read 2 more answers
Fifty-three percent of employees make judgements about their co-workers based on the cleanliness of their desk. You randomly sel
GarryVolchara [31]

Answer:

The unusual X values ​​for this model are: X = 0, 1, 2, 7, 8

Step-by-step explanation:

A binomial random variable X represents the number of successes obtained in a repetition of n Bernoulli-type trials with probability of success p. In this particular case, n = 8, and p = 0.53, therefore, the model is {8 \choose x} (0.53) ^ {x} (0.47)^{(8-x)}. So, you have:

P (X = 0) = {8 \choose 0} (0.53) ^ {0} (0.47) ^ {8} = 0.0024

P (X = 1) = {8 \choose 1} (0.53) ^ {1} (0.47) ^ {7} = 0.0215

P (X = 2) = {8 \choose 2} (0.53)^2 (0.47)^6 = 0.0848

P (X = 3) = {8 \choose 3} (0.53) ^ {3} (0.47)^5 = 0.1912

P (X = 4) = {8 \choose 4} (0.53) ^ {4} (0.47)^4} = 0.2695

P (X = 5) = {8 \choose 5} (0.53) ^ {5} (0.47)^3 = 0.2431

P (X = 6) = {8 \choose 6} (0.53) ^ {6} (0.47)^2 = 0.1371

P (X = 7) = {8 \choose 7} (0.53) ^ {7} (0.47)^ {1} = 0.0442

P (X = 8) = {8 \choose 8} (0.53)^{8} (0.47)^{0} = 0.0062

The unusual X values ​​for this model are: X = 0, 1, 7, 8

6 0
3 years ago
Read 2 more answers
11. Write the balanced equation for the reaction of HC2H3O2, with Al(OH)3 to form H2O and Al(C2H302)3:
Kamila [148]

Answer:

74.36 g of aluminium acetate.

730.27g of aluminium acetate.

- to the nearest hundredth.

Step-by-step explanation:

Acetic acid is usually written as CH3COOH.

a. 6CH3COOH + Al(OH)3 ---> Al(CH3COO)3 + 9H2O

So 6 moles of acetic acid produce 1 mole of aluminium acetate.

Using the molecular masses

6*( 1.008*4 + 12.011*2 + 16 *2) g acetic acid gives (26.98+3(36.032+ 2*12.011)

348.228 g acetic acid gives 207.142 g Al acetate.

So 125 g gives (207.142 / 348.228) * 125

= 74.36 g of aluminium acetate.

b.

(26.98 + 3*16 + 3 * 1.008) g  of Al(OH)3 gives 207.142 g Al acetate

78.004 g gives 207.142 g Al acetate

275 g gives   (207.142 / 78.004) * 275

= 730.27g Al acetate.

7 0
4 years ago
2280÷60 how to work it out
Arturiano [62]
You could do 228/6 = 38 

2280/60 = 38

hope this helps you
4 0
4 years ago
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