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Bezzdna [24]
2 years ago
12

Answer the question please: The correct answer will be marked as brainliest =) thanks xoxo

Mathematics
2 answers:
Mumz [18]2 years ago
6 0
When there is multiplication, we add the powers.. But when there is division, we subtract the powers. Therefore:

3^8 x 3^4 is 3^8+4= 3^12 (this is the numerator)

3^2x3^8 is 3^ 2+8= 3^10 (this is the denominator)

Now since there is a division bar we obviously have to divide the numerator: 3^12 by the denominator: 3^10. [Remember division requires subtraction of powers] therefore:
3^12 \ 3^10 = 3^12-10
= 3^2. (=9)
And is not given as 9 since it is not in index form therefor answer is 3 power of 2 (3^2)
Hope this is helpful for you!
Jlenok [28]2 years ago
3 0

Answer:

<h2>9</h2>

Step-by-step explanation:

Just multiply the numerator together using a calculator (for ease) then multiply the denominators including the powers. Once you did this part properly you should get,

531441/59049

= 9

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Solve<br> 2/3x+4=8 whats x?
PolarNik [594]

Answer:

x = 6

Step-by-step explanation:

\frac{2}{3} x + 4 = 8 \\  \frac{2x}{3}  = 8 - 4 \\ \frac{2x}{3 }  = 4 \\ 2x = 4 \times 3 \\ 2x = 12 \\  x= 6

6 0
3 years ago
Read 2 more answers
Let U = {1,2,3,4,5,6,7,8,9,10}, A = {1,3,5,7,9}, B = {2,4,6,8,10} and C = {1,2,3,4} find (i) U' ii) A∩A' iii) A – ( B U C) iv) A
Artyom0805 [142]

Answer:

(i) U' = Φ

(ii) A∩A' = Φ

(iii) A – ( B U C) = {5,7,9}

(iv) A' U ( B U C ) = {2,4,6,8,10}

(v) A' U ( B' ∩ C') = {2,4,5,6,7,8,9,10}

Step-by-step explanation:

8 0
2 years ago
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3 years ago
Liam has 9/10 gallon of paint for his birdhouses he sells at the fair. It takes 1/20 gallon of paint for each one. How many can
xenn [34]

Answer:

Liam can paint 18 bird houses.

Step-by-step explanation:

9/10 divided by 1/20 = 18

8 0
2 years ago
Please help me with this.
JulijaS [17]

The <em>speed</em> intervals such that the mileage of the vehicle described is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h]

<h3>How to determine the range of speed associate to desired gas mileages</h3>

In this question we have a <em>quadratic</em> function of the <em>gas</em> mileage (g), in miles per gallon, in terms of the <em>vehicle</em> speed (v), in miles per hour. Based on the information given in the statement we must solve for v the following <em>quadratic</em> function:

g = 10 + 0.7 · v - 0.01 · v²      (1)

An effective approach consists in using a <em>graphing</em> tool, in which a <em>horizontal</em> line (g = 20) is applied on the <em>maximum desired</em> mileage such that we can determine the <em>speed</em> intervals. The <em>speed</em> intervals such that the mileage of the vehicle is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h].

To learn more on quadratic functions: brainly.com/question/5975436

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3 0
2 years ago
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