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Rainbow [258]
3 years ago
5

Factor 20x2 + 25x – 12x – 15 by grouping. 1. Group terms with common factors. 2. Factor the GCF from each group. 3. Write the po

lynomial as a product of binomials.
Mathematics
2 answers:
a_sh-v [17]3 years ago
8 0

Answer:

(5x - 3) • (4x + 5)

Step-by-step explanation:

RUDIKE [14]3 years ago
5 0
<span>Step 1:
</span>
<span> (((22•5x2) + 25x) - 12x) - 15)))

</span>
<span>The first term is, <span> <span>20x2</span> </span> its coefficient is <span> 20 </span>.
The middle term is, <span> +13x </span> its coefficient is <span> 13 </span>.
The last term, "the constant", is <span> -15



</span></span>
<span>step 2 above,  -12  and  25 
                     <span>20x2 - 12x</span> + 25x - 15

Step-4 : Add up the first 2 terms, pulling out like factors :
                    4x • (5x-3)
              Add up the last 2 terms, pulling out common factors :
                    5 • (5x-3)
Step-5 : Add up the four terms of step 4 :
                    (4x+5)  •  (5x-3)
             Which is the desired factorization</span>Final result :<span> (5x - 3) • (4x + 5) </span>
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vekshin1

Answer: Choice B

(x-1)(x^3+x^2+5x+6)

==========================================

Explanation:

The 1 in the upper left box means that x = 1 is a root of the original polynomial.

So this means x-1 is a factor of the original polynomial.

This is because x = 1 leads to x-1 = 0 after subtracting 1 from both sides.

-----------------

The 0 in the last position of the bottom row shows we got a remainder of 0.

Getting a remainder 0 tells us that (x-1) is a factor of the polynomial. This synthetic division table confirms our initial guess.

The other values in that bottom row (1, 1, 5, 6) form coefficients to the polynomial 1x^3+1x^2+5x+6, or simply x^3+x^2+5x+6

-------------------

So we know that (x-1) and (x^3+x^2+5x+6) are factors

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You can confirm this by expanding out the right hand side (distribution rule).

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