Answer:
3.33 minutes (3 minutes and 20 seconds)
Explanation:
Speed of the runner = s = 5 m/s
We need to calculate how will it take for runner to complete 1 km. We have the speed, the distance and we need to find the time. Before performing any calculations, we must convert the values to same units.
Speed is in m/s and distance is in kilometers. So we have to either convert speed to km/s or distance into meters. In this case, converting distance into meters would be a convenient option.
1 kilo meters = 1000 meters
The distance, speed and time are related by the equation:
Distance = Speed x Time
So,
Time = Distance/Speed
Using the values, we get:
t = 1000/5
t = 200 seconds
This means, the runner can complete 1 kilometers in 200 seconds. Since, there are 60 seconds in a minute, we can convert this time to minutes, by dividing it by 60. i.e.

Thus, it will take the runner 3.33 minutes (3 minutes and 20 seconds) to travel 1 km.
<span>The number of oscillations that a wave completes per unit of time is called "frequency".
Frequency represents in fact how many complete cycles of the wave are done in a single unit of time. It can be written also as
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</span>
Answer:
gs = 0.6 m/s^2
Explanation:
Given data:
velocity = 12 m/s
height s = 12t -(1/2) g_s t^2
Given velocity is the derivatives of height



when velocity tend to 0 , maximum height is reached



at t = 20 sec ball reached the max height, so

The work function in eV for the given cutoff frequency is 5.05 eV.
<h3>What is cutoff frequency?</h3>
The work function is related to the frequency as
Wo = h x fo
where, fo = cutoff frequency and h is the Planck's constant
Given is the cutoff frequency for a certain element is 1.22 x 10¹⁵ Hz
Wo = 6.626 x 10⁻³⁴ x 1.22 x 10¹⁵ Hz / 1.6 x 10⁻¹⁹
Wo = 5.05 eV
Thus, the work function is 5.05 eV
Learn more about cutoff frequency.
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Answer:
125 V
Explanation:
Given,
Power ( P ) = 500 W
Current ( I ) = 4 A
To fine : -
Potential difference ( V ) = ?
Formula : -
P = V I
V = P / I
= 500 / 4
V = 125 V
Therefore,
the potential difference across the ends of the heating element is 125 V.