Answer:
The work input during this process is -742 kJ
Explanation:
Given;
Initial temperature of nitrogen T₁ = 250 K
final temperature of nitrogen T₂ = 450 K
mass of nitrogen, m = 5 kg
The work input during the process is calculated as;
where;
R is gas constant = 0.2968 kJ/kgK
substitute given values in above equation.
Therefore, the work input during this process is -742 kJ
Answer:
A. Area under force-time graph & Area under force-displacement graph
Explanation:
To find the impulse or work done the area under force-time graph and area under force-displacement graph will give us these respective values.
Impulse = Force x time
Work done = Force x displacement
When we plot a graph of force and time, the area under it is the impulse.
When a graph of force and displacement is plotted, the area under is the work done.
I think the answer is 3000 joules since work is force times distance.
unpaired electrons,are required each with a magnetic moment of 9.27 ×10⁻²⁴A.m² , to participate .
- Magnetic moment, also called magnetic dipole moment, is a measure of the tendency of an object to align with a magnetic field.
- Magnetic moment is a vector quantity. Objects tend to be placed so that their magnetic moment vectors are parallel to the lines of magnetic force.
- The direction of the magnetic moment points from the south pole of the magnet to the north pole. The magnetic field produced by a magnet is directly proportional to its magnetic moment.
"Magnetic moment is defined as the magnetic strength and orientation of a magnet or other object that produces a magnetic field."
It is given that magnetic moment of the Earth is approximately 8.00 ×10²²A.m² .
Number of unpaired is found by dividing the magnetic moment of the Earth to the given magnetic moment of 9.27 ×10⁻²⁴A.m²
Each iron atom has two unpaired electrons, so the number of iron atoms required is 
electrons.
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