Answer :
The frictional force on the block from the floor and the block's acceleration are 10.45 N and 0.73 m/s².
Explanation :
Given that,
Mass of block = 3.50
Angle = 30°
Force = 15.0 N
Coefficient of kinetic friction = 0.250
We need to calculate the frictional force
Using formula of frictional force





(II). We need to calculate the block's acceleration
Using newton's second law of motion





Hence, The frictional force on the block from the floor and the block's acceleration are 10.45 N and 0.73 m/s².
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Answer:
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Answer:

Explanation:
Given data:
0.1 L HCl × 1.020 mol/L = 0.102 mol HCL
0.05 L NaOH × 2.040 mol/L = 0.102 mol NaOH
NaOH + HCl \rightarrow H_2O + NaCl
0.102 mol HCl /1 mol HCl × 1 mol H2O = 0.102 mol H2O
0.102 mol H2O / 1 mol H2O × 57000 J = 5814 J

M(t)=150*1=150 g
we know that heat energy is given as

where c is specific heat
total energy released is = 57 \times 0.102 = 5.814 kJ


Answer:
With changing speed and/or in a circle