The number of the meals possible is 350.
The complete question is given below:-
A menu has 5 choices of appetizers, ten main courses, and seven desserts. How many meals are possible?
<h3 /><h3>What is the combination?</h3>
The arrangement of the different things or numbers in a number of ways is called the combination.
Given that:-
- A menu has 5 choices of appetizers, ten main courses, and seven desserts.
The number of the combination of the meals will be calculated as:-
N = 5 x 10 x 7
N = 350
Therefore the number of the meals possible is 350.
To know more about combinations follow
brainly.com/question/11732255
#SPJ1
S(p)= 5(12)= $60
D(p)= 120-4(12)= $72
The correct ratio for this problem is 3:4
<h2>The steps:</h2><h2>1) make 45 and 60 a fraction </h2><h2>2)45/60 simplify </h2><h2>3) once you simplfy you should get 3/4</h2><h2 /><h2>Steps in Numbers:</h2><h2>45/60 =3/4</h2><h2>60/45=4/3 convert 3/4</h2><h2>3/60=1/20 </h2><h2>3/45=1/15</h2><h2>Step 3:</h2><h2>60 divided into 48 as a fraction and simplify it </h2>
Well than look it up online and an u explain the question better
Answer:
19. (-∞,-5)U(-5,2)U(2,∞)
20. (-∞,-6)U(-6,4)U(4,∞)
21. (-∞,10)U(-10,3)U(3,7)U(7,∞)
Step-by-step explanation:
To summarize these three equations, ignore the numerators for every three equations listed, flip the + and - for each side to get the x values. You have to put the values from smallest to largest in order to state the domain. You need this sign -> U for the answers.
