False. You should have little text and lots of pictures, because you are the one who should be doing the explaining, not the presentation.
Answer:
WBS
Explanation:
<h2><u>Fill in the blanks</u></h2>
The <u>WBS</u> provides a basis for creating the project schedule and performing earned value management for measuring and forecasting project performance.
Answer:
Placeholders
Explanation: Placeholders are boxes with dotted borders that hold content in its place on a slide layout. Slide layouts contain different types of placeholders (for example, for text, pictures, videos, and more). You can change a placeholder by resizing or repositioning it on a slide layout. You can also delete a placeholder.
The recursive function would work like this: the n-th odd number is 2n-1. With each iteration, we return the sum of 2n-1 and the sum of the first n-1 odd numbers. The break case is when we have the sum of the first odd number, which is 1, and we return 1.
int recursiveOddSum(int n) {
if(2n-1==1) return 1;
return (2n-1) + recursiveOddSum(n-1);
}
To prove the correctness of this algorithm by induction, we start from the base case as usual:
by definition of the break case, and 1 is indeed the sum of the first odd number (it is a degenerate sum of only one term).
Now we can assume that 
returns indeed the sum of the first n-1 odd numbers, and we have to proof that 
returns the sum of the first n odd numbers. By the recursive logic, we have
and by induction, is the sum of the first n-1 odd numbers, and 2n-1 is the n-th odd number. So, is the sum of the first n odd numbers, as required:
