For part (a), first consider the simple case where we roll two dice.What is the probability that the second roll is greater than the first? Assuming a six-sided dice, the total number of outcomes $(i,j)$ is $6^2$.
Answer:
For the rectangle
Length=ℓ
Breadth=b
Area is 12 cm2
ℓb=12
Perimeter is 16 cm
2(ℓ+b)=16
ℓ+b=8
Substitute b=12ℓ from first equation
ℓ+12ℓ=8
ℓ2+12=8ℓ
ℓ2−8ℓ+12=0
Use quadratic formula (x=−b±√b2−4ac2a) to find ℓ
ℓ=−(−8)±√(−8)2−(4×1×12)2×1
ℓ=8±√162
ℓ=8±42
ℓ1=8+42=6
ℓ2=8−42
Step-by-step explanation:
For the rectangle
Length=ℓ
Breadth=b
Area is 12 cm2
ℓb=12
Perimeter is 16 cm
2(ℓ+b)=16
ℓ+b=8
Substitute b=12ℓ from first equation
ℓ+12ℓ=8
ℓ2+12=8ℓ
ℓ2−8ℓ+12=0
Use quadratic formula (x=−b±√b2−4ac2a) to find ℓ
ℓ=−(−8)±√(−8)2−(4×1×12)2×1
ℓ=8±√162
ℓ=8±42
ℓ1=8+42=6
ℓ2=8−42
Answer:
it would be small.
Step-by-step explanation:
bcause its the smallest one and theres only 1 softball.
With DC = AB, you have a pair of sides.
Then with the parallel lines, you get angles 2 and 3 are congruent because they are alternate interior angles.
Finally, side AC is congruent to side AC. That gives you another pair of congruent sides.
You can use SAS.
