4 years ago

8over 20= y over 60 what is y

Mathematics

1 answer:

Pachacha [2.7K]4 years ago

6 0

The answer to the problem is 24

You might be interested in

57 divided by 2 [with a remainder]

jenyasd209 [6]

Answer: 28 r 1

Step-by-step explanation:

4 0

2 years ago

The coordinate (0,0) is a point on the graph y = 2x.<br> True<br> False

Amanda [17]

Yes because it’s linear

4 0

4 years ago

Read 2 more answers

Given a cylinder with radius of 5 cm and a height of 8 cm find the volume of the cylinder use 3.14 for pie

oksian1 [2.3K]

Answer:

628.32

Step-by-step explanation:

V=πr2h=π·52·8≈628.31853

8 0

3 years ago

Read 2 more answers

What is the ratio of 3 to 9

son4ous [18]

Answer:

the ratio of 3 to 9 is 1/3

Step-by-step explanation:

8 0

3 years ago

Use the properties of limits to help decide whether the limit exists. If the limit exists, find its value. ModifyingBelow lim W

Sergeu [11.5K]

Answer:

The value of given limit problem is 0.

Step-by-step explanation:

The given limit problem is

$lim_{x\rightarrow \infty}\dfrac{6x^3+5x-7}{6x^4-4x^3-9}$

We need to find the value of given limit problem.

Divide the numerator and denominator by the leading term of the denominator, i.e., $x^4$

$lim_{x\rightarrow \infty}\dfrac{\frac{6x^3+5x-7}{x^4}}{\frac{6x^4-4x^3-9}{x^4}}$

$lim_{x\rightarrow \infty}\dfrac{\frac{6}{x}+\frac{5}{x^3}-\frac{7}{x^4}}{6-\frac{4}{x}-\frac{9}{x^4}}$

Apply limit.

$\dfrac{\frac{6}{ \infty}+\frac{5}{ \infty}-\frac{7}{ \infty}}{6-\frac{4}{ \infty}-\frac{9}{ \infty}}$

We know that $\frac{1}{\infty}=0$ .

$\dfrac{0+0-0}{6-0-0}$

$\dfrac{0}{6}$

$0$

Hence, the value of given limit is 0.

8 0

3 years ago