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Mariana [72]
3 years ago
5

Calculate s24 for the arithmetic sequence in which a13=1.9 and the common difference is d=3.7.

Mathematics
2 answers:
adell [148]3 years ago
8 0

Answer:

Just took this test the correct answer is 1.2


kolbaska11 [484]3 years ago
3 0

<u>Answer:</u>

The correct answer option is 42.6.

<u>Step-by-step explanation:</u>

We know that in a arithmetic sequence, a_{13}=1.9 and the common difference is (d)=3.7.

The standard form of an arithmetic sequence is given by:

a_n=a_1+(n-1)d

So we will substitute the given values in this formula to find the value of a_1.

a_{13}=a_1+(13-1)3.7

1.9=a_1+(12)3.7

1.9=a_1+44.4

a_1=-42.5

Now finding the 24th term"

S_{24}=a_1+(n-1)d\\\\S_{24}=-42.5+(24-1)3.7\\\\\\S_{24}=42.6.

Therefore, the 24th term of the given arithmetic sequence is 42.6.


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Solve the equation using the quadratic formula : x^2-10x+25=18
Sever21 [200]
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x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{10- 6\sqrt{2}}{2}=\frac{2(5-3\sqrt{2})}{2}= 5-3\sqrt{2}\\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{10+ 6\sqrt{2}}{2}=\frac{2(5+3\sqrt{2})}{2}= 5+3\sqrt{2}


Answer : \ x= 5-3\sqrt{2} \ \ or \ \ x = 5+3\sqrt{2}


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Step-by-step explanation:

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