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Dafna11 [192]
3 years ago
12

Dylan has two cubes of iron. The larger cube has twice the mass of the smaller cube. He measures the smaller cube. Its mass is 2

0 grams, and its density is 7.87 g/cm3. What’s the larger cube’s volume? The larger cube’s volume is about cm3.
Physics
1 answer:
Lina20 [59]3 years ago
6 0

Answer:

5.08cm³

Explanation:

Given parameters

The larger cube has twice the mass of the smaller cube

Mass of smaller cube = 20g

Mass of the larger cube = 2 x 20  = 40g

Density of the smaller cube  = 7.87g/cm³

Unknown:

Volume of the larger cube = ?

Solution:

Density is the mass per unit volume of substance. For all samples of a substance, the density value is the same.

So, the density of the small and large iron is the same

   Density  = \frac{mass}{volume}  

        Volume  = \frac{mass}{density}  

 So;

  Volume of larger cube  = \frac{40}{7.87}  = 5.08cm³

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An object of mass m is traveling in a circle with centripetal force Fc. If the velocity of the object is v, what is the radius o
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40 x 10 = 400.

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Read 2 more answers
A uniform beam XY is 100 cm long and weighs 4.0N.The beam rests on a pivot 60 cm from end X. A load of 8.0 N hangs from the beam
Alex777 [14]

Answer:

<h2>The magnitude of force F is 18N</h2>

Explanation:

The magnitude of the force in the set up can be solved for using the principle of moment. According to the principle, the sum of clockwise moment  is equal to the sum of anticlockwise moments.

Moment = Force * perpendicular distance

Clockwise moments;

The force that acts clockwise is the unknown Force F and 4N force. If the  beam rests on a pivot 60 cm from end X and a Force F acts on the beam 80 cm from end X, the perpendicular distance of the force F from the pivot is 80-60 = 20cm and the perpendicular distance of the 4N force from the pivot is 60-50 = 10cm

Moment of force F about the pivot = F * 20

Moment of 4N force about the pivot = 4*10 = 40Nm

Sum of clockwise moment = 40+20F...(1)

Anticlockwise moment;

The  8N will act anticlockwisely about the pivot.

The distance between the 8N force and the pivot is 60-10 = 50cm

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=400Nm...(1)

Equating 1 and 2 we have;

40+20F = 400

20F = 400-40

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F = 18N

The magnitude of force F is 18N

6 0
4 years ago
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