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Dafna11 [192]
3 years ago
12

Dylan has two cubes of iron. The larger cube has twice the mass of the smaller cube. He measures the smaller cube. Its mass is 2

0 grams, and its density is 7.87 g/cm3. What’s the larger cube’s volume? The larger cube’s volume is about cm3.
Physics
1 answer:
Lina20 [59]3 years ago
6 0

Answer:

5.08cm³

Explanation:

Given parameters

The larger cube has twice the mass of the smaller cube

Mass of smaller cube = 20g

Mass of the larger cube = 2 x 20  = 40g

Density of the smaller cube  = 7.87g/cm³

Unknown:

Volume of the larger cube = ?

Solution:

Density is the mass per unit volume of substance. For all samples of a substance, the density value is the same.

So, the density of the small and large iron is the same

   Density  = \frac{mass}{volume}  

        Volume  = \frac{mass}{density}  

 So;

  Volume of larger cube  = \frac{40}{7.87}  = 5.08cm³

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A student stands on the edge of a cliff that is 300 m high and kicks a rock horizontally. 7.8 seconds later, the rock hits the g
mart [117]

Answer:

6.65m/s

Explanation:

Using the equation of motion

S = ut + 1/2gt²

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t is the time

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Given

S = 300 + 50

S = 350m

t = 7.8seconds

g = 9.8m/s^2

Get S

S = 7.8u + 1/2(9.8)(7.8)²

S = 7.8u + 298.116

350 = 7.8u + 298.116

7.8u = 350 - 298.116

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6 0
3 years ago
We would like to use the relation V(t)=I(t)RV(t)=I(t)R to find the voltage and current in the circuit as functions of time. To d
drek231 [11]

Answer:

V = -RC (dV/dt)

Solving the differential equation,

V(t) = V₀ e⁻ᵏᵗ

where k = RC

Explanation:

V(t) = I(t) × R

The Current through the capacitor is given as the time rate of change of charge on the capacitor.

I(t) = -dQ/dt

But, the charge on a capacitor is given as

Q = CV

(dQ/dt) = (d/dt) (CV)

Since C is constant,

(dQ/dt) = (CdV/dt)

V(t) = I(t) × R

V(t) = -(CdV/dt) × R

V = -RC (dV/dt)

(dV/dt) = -(RC/V)

(dV/V) = -RC dt

∫ (dV/V) = ∫ -RC dt

Let k = RC

∫ (dV/V) = ∫ -k dt

Integrating the the left hand side from V₀ (the initial voltage of the capacitor) to V (the voltage of the resistor at any time) and the right hand side from 0 to t.

In V - In V₀ = -kt

In(V/V₀) = - kt

(V/V₀) = e⁻ᵏᵗ

V = V₀ e⁻ᵏᵗ

V(t) = V₀ e⁻ᵏᵗ

Hope this Helps!!!

5 0
4 years ago
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