If the framed picture is shaped like a square and has a 12 square foot surface area, then the answer is yes, it will fit flush against the edge of the crate.
Given Part A:
the volume of the cube = 64 cubic feet
therefore, ∛64 = 4 feet
hence one edge measures 4 feet.
Now for Part B:
the area of the square is 12 square feet.
hence, √12 = 3.36 feet.
we can observe that 3.46<4
which indicates that the area covered by the painting is less than that of the one side of the crate, which makes it easy for the painting to fit in the crate.
Hence the painting will fit a side of crate.
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While packing for their cross-country move, the Chen family uses a that has the shape of a cube. PART A PART B If the crate has the volume V = 64 cubic feet, The Chens want to pack a large, framed painting. If an area of 12 square feet , will the painting fit flat what is the length of one edge? the framed painting has the shape of a square with against a side of the crate? Explain.
Answer:
Statements 3, 4 and 5 are true.
Step-by-step explanation:
x^2 - 8x + 4
Using the quadratic formula:
x = [ -(-8) +/- √((-8)^2 - 4*1*4)] / 2
= (8 +/- √(64 - 16)) / 2
= 4 +/- √48 / 2
= 4 +/- 4√3/2
= 4 +/- 2√3.
So the third statement is true.
Converting to vertex form:
x^2 - 8x + 4
= (x - 4)^2 - 16 + 4
= (x - 4)^2 -12
So the extreme value is at (4, -12)
So the fourth statement is true.
The coefficient of the term in x^2 is 1 (positive) so the graph has a minimum.
Answer:
Im not good at math
Step-by-step explanation:
I think it's 1/2, which is 6/12.
5/12 plus 1/12 equals 6/12. 6 is half of 12, so you one half. I hoped this helped.
{(–1, 1), (–2, 1), (–2, 2), (0, 2)}
In a function, each input has an output
Each domain has a range. In a function, range can be repeated but domain cannot be repeated. Same domain cannot have two range values.
Here domain is {-1, -2, -2, 0}
Range is { 1, 1, 2, 2}
Domain -2 is repeating so this relation is not a function
Answer : No; a domain value has two range values.
