A boy throws a ball into the air. The equation h=−16t^2+23t+4 models the path of the ball, where h is the height (in feet) of th
e ball t seconds after it is thrown. How long is the ball in the air?
1 answer:
Answer:
0.72secs
Step-by-step explanation:
Given the height of the ball in air modeled by the equation:
h=−16t²+23t+4
Required
Total time it spent in the air
To get this we need to calculate its time at the maximum height
At the maximum height,
v = dh/dt = 0
-32t + 23 = 0
-32t = -23
t = 23/32
t = 0.72secs
<em>Hence the total time it spend in the air will be 0.72secs</em>
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