A boy throws a ball into the air. The equation h=−16t^2+23t+4 models the path of the ball, where h is the height (in feet) of th

Question

3 years ago

11

e ball t seconds after it is thrown. How long is the ball in the air?

1 answer:

lina2011 [118] · Answer 1 · 2022-02-19T02:35:16+03:00

Answer:

0.72secs

Step-by-step explanation:

Given the height of the ball in air modeled by the equation:

h=−16t²+23t+4

Required

Total time it spent in the air

To get this we need to calculate its time at the maximum height

At the maximum height,

v = dh/dt = 0

-32t + 23 = 0

-32t = -23

t = 23/32

t = 0.72secs

<em>Hence the total time it spend in the air will be 0.72secs</em>