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stira [4]
3 years ago
15

Which algebraic expression is equivalent to the expression below? 8(4x + 6) + 19

Mathematics
1 answer:
Brrunno [24]3 years ago
5 0

Answer:

The answer is 32x+67

Step-by-step explanation:

You might be interested in
40 POINTS. When they form conical piles, granular materials such as salt, gravel, and sand settle at different "angles of repose
grandymaker [24]

Answer:

34.0 degrees, 29.6 feet in Diameter.

This is a right triangle trigonometry question.

Use half of the diameter to form the base of the triangle (19.3 ft) with a height 0f 13.

Use Inverse Tangent function to find the angle of repose

round to 34.0

then use the angle of repose to solve trigonometric function of the tangent for the radius of the other cone.

switch denominator and tangent

multiply by 2 to get diameter of second cone

14.82*2≈29.6

hopefully this helps!

7 0
3 years ago
Is expression K+W show the sum of K and W ?
ArbitrLikvidat [17]

Answer:

yes

Step-by-step explanation:

4 0
3 years ago
851.643 as a mixed number
Scorpion4ik [409]

Answer:

851 and 643/1000

Step-by-step explanation:

use a calculator yeet actually just like take the second part and put it over thousandths

8 0
3 years ago
Find the missing side length ​
lidiya [134]

Answer:

The length of the missing side is

4 \sqrt{5}  \\ if \: you \: want \: it \: not \: simplified \: it \: would \: be \: \\  \sqrt{80}

Step-by-step explanation:

You could do Pythagorean theorem which is:

{a}^{2}  +  {b}^{2}  =  {c}^{2}  \\ {8}^{2}  +  {4}^{2}  =  {c}^{2}  \\{64}  +  {16}  =  {c}^{2}  \\  \sqrt{80}  =  {c}^{2}  \\   4\sqrt{5}  = c

7 0
3 years ago
Prove: The product of the slopes of lines AC and BC is -1.
kicyunya [14]

Given that the AC and BC are perpendicular, their slopes are the negative inverse of each other which gives that the product of the slopes of AC and BC is -1

<h3>How can the prove that the product of the slopes is -1 be found?</h3>

The completed proof is presented as follows;

The slope of AC or GC is GF/FC by definition of slope. The slope of BC or CE is DE/CD by definition of slope.

<FCD = <FCG + <GCE + <ECD <u>by angle addition property </u> <FCD = 180° by the definition of a straight angle, and <GCE = 90° by definition of perpendicular lines. So by substitution property of equality 180° = <FCG + 90° + <ECD. Therefore 90° - <FCG = <ECD, by the <u>subtraction property of equality </u> . We also know that 180° = <FCG + 90° + <CGF by the triangle sum theorem and by the subtraction property of equality 90° - <FCG = <CGF, therefore <ECD = <CGF by the substitution property of equality. Then <ECD ≈ <CGF by the definition of congruent angles. <GFC ≈ <CDE because all right angles are congruent. So by AA ∆GFC ~ ∆CDE. Since <u>the ratio of corresponding sides of similar triangles are equal</u> then GF/CD = FC/DE or GF•DE = CD•FC by cross product. Finally, by the division property of equality GF/FC = CD/DE. We can multiply both sides using the slope of using the <u>multiplication property of equality </u> to get GF/FC × -DE/CD = CD/DE × -DE/CD. Simplify so that GF/FC × -DE/CD = -1. This shows that the product of the slopes of AC and BC is -1.

Learn more about perpendicular lines here:

brainly.com/question/20475360

#SPJ1

6 0
2 years ago
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