Answer:
2 real solutions
Step-by-step explanation:
Given a quadratic equation in standard form
ax² + bx + c = 0 ( a ≠ 0 ), then the discriminant is
Δ = b² - 4ac
• If b² - 4ac > 0 then 2 real and distinct solutions
• If b² - 4ac = 0 then 2 real and equal solutions
• If b² - 4ac < 0 then no real solutions
x² + 4x - 3 = 0 ← is in standard form
with a = 1, b = 4, c = - 3 , then
b² - 4ac = 4² - (4× 1 × - 3) = 16 - (- 12) = 16 + 12 = 28
Since b² - 4ac > 0 then the equation has 2 real and distinct solutions
The line 6x - 2y = 12 goes through -6 on the y-axis and 2 on the x-axis ie through (0, -6) and (2, 0)
The line will be solid and shaded above (towards the origin)
There are an infinite number of choices for the example points!
Here is my selection.
(0, 0) is in the solution set. 6 x 0 - 2 x 0 = 0 which is less than 12
(5, 0) is not in the solution set. 6 x 5 - 2 x 0 = 30 which is greater than 12
(2, 0) is on the line. 6 x 2 - 2 x 0 = 12
Answer:
D
Step-by-step explanation:
Factor 16 and see the - factor pairs and add them, see which add to -12
-1-16=-17 nope
-2-8=-10 nope
-4-4=-8
hmm
we will solve with math
xy=16
x+y=-12
minus x both sides
y=-12-x
sub for y in other equation
x(-12-x)=16
-12x-x^2=16
add 12x+x^2 both sides
0=x^2+12x+16
use quadratic formula
if you have
ax^2+bx+c=0
x=

0=x^2+12x+16
a=1
b=12
c=16
x=

x=

x=

x=

x=

x=

or

aprox
x=-1.52786 or -10.4721
those are the numbers
the numbes are -1.52786 or -10.4721