2 years ago

Do you think Locke would have supported the colonists' actions in the boston tea party?why?why not?

1 answer:

3 0

<span>Yes. By that time, the British colonists were more known as American patriots. So I do in fact believe he would have supported it.

Hope this helped. Have a great night!</span>

You might be interested in

What is the slope of the line through (-7,-8) and (0,4)

Oksanka [162]

Answer:

c.12/7

Step-by-step explanation:

3 0

2 years ago

when making pink paint, the art teacher uses the ratio 3:2. For every 3 cups of white paint she used in the mixture, she needs t

Vlad [161]

Whats the question ??

7 0

2 years ago

What is ROI?

Elza [17]

A) or C) not sure

Maybe

6 0

2 years ago

Read 2 more answers

50 points to whoever answers all my questions, have to have discord, go add Clorox#6224

CaHeK987 [17]

Answer:

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Find the missing lengths: <br> HI=7 and LH=9, find LK.

Katarina [22]

Answer:

LK=12

Step-by-step explanation:

From the given figure, HI=7 and LH=9, and we know that

$(KH)^{2}=(IH)(HL)$

$(KH)^{2}=7{\times}9$

$(KH)^{2}=63$ (1)

Now, from ΔKHL, we have

$(OH)^{2}=(OK)(OL)$

and from ΔOKH,

$(KH)^{2}=(OH)^{2}+(OK)^2$

$(OK)^2=(KH)^2-(OH)^2$

$(OK)^2=63-(OK)(OL)$

$(OK)^2+(OK)(OL)=63$

$OK(OK+OL)=63$

$OK(KL)=63$ (2)

Also, ΔIKL is similar to ΔOHL, therefore

$\frac{OL}{KL}=\frac{9}{16}$

$\frac{KL-OK}{KL}=\frac{9}{16}$

$1-\frac{OK}{KL}=\frac{9}{16}$

$\frac{7}{16}=\frac{OK}{KL}$

Using equation (2), we get

$\frac{7}{16}=\frac{63}{(KL)^2}$

$(KL)^2=\frac{1008}{7}$

$(KL)^2=144$

$KL=12$

Thus, the value of LK is 12.

8 0

3 years ago