All categories

3 years ago

Do you think Locke would have supported the colonists' actions in the boston tea party?why?why not?

1 answer:

3 0

<span>Yes. By that time, the British colonists were more known as American patriots. So I do in fact believe he would have supported it.

Hope this helped. Have a great night!</span>

You might be interested in

Find the discriminant of X^2+ 4x - 3 = 0

Drupady [299]

Answer:

2 real solutions

Step-by-step explanation:

Given a quadratic equation in standard form

ax² + bx + c = 0 ( a ≠ 0 ), then the discriminant is

Δ = b² - 4ac

• If b² - 4ac > 0 then 2 real and distinct solutions

• If b² - 4ac = 0 then 2 real and equal solutions

• If b² - 4ac < 0 then no real solutions

x² + 4x - 3 = 0 ← is in standard form

with a = 1, b = 4, c = - 3 , then

b² - 4ac = 4² - (4× 1 × - 3) = 16 - (- 12) = 16 + 12 = 28

Since b² - 4ac > 0 then the equation has 2 real and distinct solutions

5 0

3 years ago

2.) Using any tool (Desmos or by hand on scratch paper) graph the inequality. Select 3 points. One point should

insens350 [35]

The line 6x - 2y = 12 goes through -6 on the y-axis and 2 on the x-axis ie through (0, -6) and (2, 0)
The line will be solid and shaded above (towards the origin)

There are an infinite number of choices for the example points!
Here is my selection.
(0, 0) is in the solution set. 6 x 0 - 2 x 0 = 0 which is less than 12
(5, 0) is not in the solution set. 6 x 5 - 2 x 0 = 30 which is greater than 12
(2, 0) is on the line. 6 x 2 - 2 x 0 = 12

5 0

3 years ago

Two numbers are respectively 40% and 60% more than a third number. The ratio of the two numbers is:

Mekhanik [1.2K]

Answer:

7:8

Step-by-step explanation:

7 0

3 years ago

Please help!!!!!I’ll mark you as brainliest!!!!!!

Sav [38]

Answer:

Step-by-step explanation:

7 0

3 years ago

What multiplies to 16 and adds to negative 12

Romashka-Z-Leto [24]

Factor 16 and see the - factor pairs and add them, see which add to -12
-1-16=-17 nope
-2-8=-10 nope
-4-4=-8
hmm

we will solve with math
xy=16
x+y=-12
minus x both sides
y=-12-x
sub for y in other equation
x(-12-x)=16
-12x-x^2=16
add 12x+x^2 both sides
0=x^2+12x+16
use quadratic formula
if you have
ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}$

0=x^2+12x+16
a=1
b=12
c=16

x= $\frac{-12+/- \sqrt{12^{2}-4(1)(16) }}{2(1)}$
x= $\frac{-12+/- \sqrt{144-64 }}{2}$
x= $\frac{-12+/- \sqrt{80}}{2}$
x= $\frac{-12+/- 4\sqrt{5}}{2}$
x= $\frac{-6+/- 2\sqrt{5}$
x= $\frac{-6+ 2\sqrt{5}$ or $\frac{-6- 2\sqrt{5}$

aprox
x=-1.52786 or -10.4721

those are the numbers

the numbes are -1.52786 or -10.4721

6 0

3 years ago

Read 2 more answers