Answer:
C x=6
Step-by-step explanation:
sqrt(x+3) = x-3
Square each side
(sqrt(x+3))^2 = (x-3)^2
x+3 = (x-3)^2
x+3 = (x-3)(x-3)
FOIL
x+3 = x^2 -3x-3x+9
Combine like terms
x+3 = x^2 -6x+9
Subtract x from each side
x-x+3 = x^2 -6x-x +9
3 = x^2 -7x +9
Subtract 3 from each side
3-3 = x^2 -7x +9-3
0 = x^2 -7x+6
Factor
0 = (x-6)(x-1)
Using the zero product property
x-6=0 x-1 =0
x=6 x=1
Since we squared we need to check for extraneous solutions
x=1
sqrt(1+3) = 1-3
sqrt(4) = -2
2=-2
False
Extraneous
x=6
sqrt(6+3) = 6-3
sqrt(9) = 3
3=3
True solutions
Answer:
26-x
Step-by-step explanation:
If he started with 26 learners he lost x. Imagine x was a value of 5. To get the learners left you will have to subtract the numbers he lost from 26
Idk honestly, haven’t cryied since I ate a warhead
....................................................
5x -2 = 63
<u> +2 = +2 (add 2 to both sides)</u>
<u>5x = 65 (your equation)</u>
5 5 (divide both sides by 5)
x = 13
Billy is 13 years old.
(check: 13 x 5 - 2 = 63
