Answer: The correct graph is the bottom left graph.
Step-by-step explanation:
Given function is f(x)=ceil(x+1)
To plot graph of f(x) in interval of(-3,3) :
ceil(x+1) is ceiling function
The output of ceil(x) is least integer greater than x
for example ceil(5.5)=6
For an interval of (-3,-2):
Take x=(-2.4)
x+1=(-1.4)
y=f(x)=ceil(x+1)=(-1)
Similarly,
For an interval of (-2,-1):
Take x=(-1.4)
x+1=(-0.4)
y=f(x)=ceil(x+1)=(0)
For an interval of (-1,0)
y=f(x)=1
For an interval of (0,1)
y=f(x)=2
For an interval of (1,2)
y=f(x)=3
For an interval of (2,3)
y=f(x)=4
Thus, The correct graph is the bottom left graph.
Answer:
3.46
Step-by-step explanation:
add
<h3>
Answer: 16</h3>
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Explanation:
Equate s(t(x)) and s(1) to find that t(x) = 1 must be the case.
Let's find what x must be.
t(x) = 3x-8
1 = 3x-8
1+8 = 3x
9 = 3x
3x = 9
x = 9/3
x = 3
So plugging x = 3 into t(x) gets us t(x) = 1
In other words, t(3) = 1
So that tells us s(t(3)) = s(1)
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Let's plug x = 3 into the s(t(x)) equation
s(t(x)) = x^2 + 3x - 2
s(t(3)) = (3)^2 + 3(3) - 2
s(1) = 9 + 3(3) - 2
s(1) = 9 + 9 - 2
s(1) = 18 - 2
s(1) = 16
Answer: uh I think its a carrot, sorry i hope this could maybe help :)
Step-by-step explanation:
