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LekaFEV [45]
3 years ago
7

Please help with this math question

Mathematics
1 answer:
marin [14]3 years ago
7 0

Answer:

78

Step-by-step explanation:

mmmionnbuyffytcvfgh ftvtkyugh gvhgjyh,guv ffghtgvj

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If the width of a rectangle is 3 and the perimeter is 20 what is the missing side length
I am Lyosha [343]
The formula to find the perimeter of a rectangle is:

P = 2(l + w)

plug in your known values to solve for the unknown

20 = 2(l + 3)
20 = 2l + 6
14 = 2l
14/2 = l
7 = l or l = 7

you can check this by plugging your l value into the equation

P = 2(l + w)
20 = 2(7 + 3)
20 = 2(10)
20 = 20

hope this helps :)



8 0
4 years ago
Jason and Britton are driving to St. George. Jason got a 20 mile head start and drove an
harina [27]

Answer:

  2 hours, 150 miles

Step-by-step explanation:

The relation between time, speed, and distance can be used to solve this problem. It can work well to consider just the distance between the drivers, and the speed at which that is changing.

<h3>Separation distance</h3>

Jason got a head start of 20 miles, so that is the initial separation between the two drivers.

<h3>Closure speed</h3>

Jason is driving 10 mph faster than Britton, so is closing the initial separation gap at that rate.

<h3>Closure time</h3>

The relevant relation is ...

  time = distance/speed

Then the time it takes to reduce the separation distance to zero is ...

  closure time = separation distance / closure speed = 20 mi / (10 mi/h)

  closure time = 2 h

Britton will catch up to Jason after 2 hours. In that time, Britton will have driven (2 h)(75 mi/h) = 150 miles.

__

<em>Additional comment</em>

The attached graph shows the distance driven as a function of time from when Britton started. The distances will be equal after 2 hours, meaning the drivers are in the same place, 150 miles from their starting spot.

3 0
2 years ago
I need somebody to say they like me so i can beat my friend in a challenge
faust18 [17]

Answer: i like you!!!!!!!!!<3

Step-by-step explanation:

4 0
3 years ago
Hours spent volunteering
iris [78.8K]

Answer:

week mo naman salamat sa points

7 0
2 years ago
In a sample of 115 115 curtains, the average length was found to be 32.2in. 32.2 ⁢ in. With a standard deviation of 0.8 0.8 . Gi
pentagon [3]

Answer:

The point estimate for the population standard deviation of the length of the curtains is 8.58in.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

s = 0.8, n = 115

The point estimate for the population standard deviation of the length of the curtains is \sigma. So

s = \frac{\sigma}{\sqrt{n}}

\sigma = s\sqrt{n}

\sigma = 0.8\sqrt{115}

\sigma = 8.58

The point estimate for the population standard deviation of the length of the curtains is 8.58in.

3 0
3 years ago
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