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Nookie1986 [14]
3 years ago
6

Evaluate f(-7). f(x)=3x^2 a) -441 b) -147 c) 78 d) 147

Mathematics
1 answer:
vlabodo [156]3 years ago
7 0

Answer:

a

Step-by-step explanation:

replace x with -7

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Bobby knows that the perimeter of the original rectangle is 120 meters. He also knows that the perimeter of the reduced rectangl
Whitepunk [10]

Answer:

<u>24 meters</u> is the width of the original rectangle.

Step-by-step explanation:

Given:

Bobby knows that the perimeter of the original rectangle is 120 meters. He also knows that the perimeter of the reduced rectangle is 30 meters and the reduced rectangle has a length of 9 meters.

Now, to get the width of original rectangle.

The reduced rectangle's perimeter = 30 meters.

The reduced rectangle's length = 9 meters.

Now, we find the width of reduced rectangle by using formula:

Let the width of reduced rectangle be x.

Perimeter=2\times length+2\times width

30=2\times 9+2\times x

30=18+2x

<em>Subtracting both sides by 18 we get:</em>

<em />12=2x<em />

<em>Dividing both sides by 2 we get:</em>

6=x\\\\x=6\ meters.

The width of reduced rectangle = 6 meters.

Now, to get the width of original rectangle:

Let the width of original rectangle be w.

<em>As given, the perimeter of the original rectangle = 120 meters.</em>

<em>And, the perimeter of reduced rectangle is 30 meters and its width is 6 meters.</em>

<em>So, 30 is equivalent to 6.</em>

<em>Thus, 120 is equivalent to </em>w.<em />

Now, to get the width using cross multiplication method:

\frac{30}{6}=\frac{120}{w}

<em>By cross multiplying we get:</em>

<em />30w=720<em />

<em>Dividing both sides by 30 we get:</em>

<em />w=24\ meters.<em />

<em>The width of original rectangle = 24 meters.</em>

Therefore, 24 meters is the width of the original rectangle.

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3 years ago
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Answer:

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Step-by-step explanation:

Given functions: h(x) = (fog)(x)   , h(x) = 3√x + 3   and f(x) = 3√x + 2

To find: function g(x)

Consider,

(fog)(x) = h(x)

f( g(x) ) = h(x)

3\sqrt{g(x)}+2=3\sqrt{x}+3

3\sqrt{g(x)}=3\sqrt{x}+1

\sqrt{g(x)}=\frac{3\sqrt{x}+1}{3}

\sqrt{g(x)}=\sqrt{x}+\frac{1}{3}

g(x)=(\sqrt{x}+\frac{1}{3})^2

g(x)=(\sqrt{x})^2+(\frac{1}{3})^2+2\times\frac{1}{3}\times\sqrt{x}

g(x)=x+\frac{1}{9}+\frac{2\sqrt{x}}{3}

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