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4 years ago

Using the PACED decision-making model, select the best tires for Ray?

2 answers:

7 0

What are some of the tires Ray would be able to use. Then break it down to what tire would be probably be the most durable, the most long lasting, which ones are safer, and which one have the best tread. Then you would be able to make your decision.

Anestetic [448]4 years ago

3 0

The correct answer to this open question is the following.

We are going to use the PACED decision-making model to select the best tires.

The first stage of the PACED model is to define the PROBLEM. Ray has to identify what is his necessity to address the situation. Here, the situation is that he needs new tires for his car. Then, the second stage is ALTERNATIVES. He has to look for some suppliers that are in the market and the locations where he can purchase them. Nex, the CRITERIA. What are the characteristics he needs for his tires? The price ranges, the style, the models, the quality of the tire. Next, he needs to EVALUATE the alternatives taking into consideration the above-mentioned factors. And finally, he has to make a DECISION in time so he can get the best option in the market.

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3 years ago

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3 years ago

Write a function named test_sqrt that prints a table like the following using a while loop, where "diff" is the absolute value o

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The function illustrated the use and the application of the while loops

While loops are used to perform iterative operations

The test_sqrt function in Python is as follows:

#This imports the math module

import math

#This defines the test_sqrt function

def test_sqrt():

#This initializes variable a to 1

a = 1

#The following is iterated for the values of variable a from 1 to 25

while a<=25

#This prints the required output

print('a =', a,'| my_sqrt(a) =',my_sqrt(a),'| math.sqrt(a) =', math.sqrt(a),'| diff =', abs(math.sqrt(a)-my_sqrt(a)))

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Note that:

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brainly.com/question/12736327

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2 years ago

The width of a rectangle is to third the length. When each dimension is decreased by 2 cm, the area is decreased by 32 cm period

mario62 [17]

Hey there!!

Basic formula :

Area of a rectangle = Length × breadth

Given :

Width = two third of the length

......................................................

Let's take the dimension of the length as ' x '

Then the breadth would be = 2x / 3

Area = ( x ) × ( 2x / 3 )

Area = 2x² / 3

........................................................

Each dimension is decreased by 2

This states that we will need to add 2 to both length and breadth

.......................................................

Length = x - 2

Breadth = 2x / 3 - 2

= 2x - 6 / 3

Area = ( x - 2 ) × ( 2x - 6 / 3 )

Area = 2x² - 10x + 12 / 3

.................................................

What they say?

Area is decreased by 32 cm

Which means..

If we add 32 to the new rectangles area , the areas would be equal to the new and the old rectangle

2x² / 3 = ( 2x² - 10x + 12 / 3 ) + ( 32 )

2x² / 3 = 2x² - 10x + 108 / 3

Multiplying by 3 on both sides

2x² = 2x² - 10x + 108

Adding 10x on both sides

2x² + 10x = 2x² + 108

subtracting by 2x² on both sides

10x = 108

Dividing by 10 on bot sides

x = 10.8

Length of the original rectangle = 10.8 cm

Breadth = 2 ( 10.8 ) / 3

= 7.2 cm

Hope my answer helps!

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3 years ago

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