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just olya [345]
3 years ago
15

Solve the inequality 16<32t

Mathematics
1 answer:
nata0808 [166]3 years ago
5 0
<span>16 < 32t
16/32 < t
1/2 < t

t </span>∈ (1/2, +∞)
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Which polynomial can be simplified to a difference of squares
Mrrafil [7]
<h2>Hello!</h2>

The answer is:

The polynomial that can be simplified to a difference of squares is the second polynomial:

16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}=(4-1)(4+1)

<h2>Why?</h2>

To solve this problem, we need to look for which of the given quadratic terms given for the different polynomials can be a result of squaring (elevating by two).

So,

Discarding, we have:

The quadratic terms of the given polynomials are:

First=10a^{2}

Second=16a^{2}

Third=25a^{2}

Fourth=24a^{2}

We have that the coefficients of the quadratic terms that can be obtained by squaring are:

16a^{2} =(4a)^{2} \\\\25a^{2} =(5a)^{2}

The other two coefficients are not perfect squares since they can not be obtained by square rooting whole numbers.

So, the first and the fourth polynomial are discarded and cannot be simplified to a difference of squares at least using whole numbers.

Therefore, we need to work with the second and the third polynomial.

For the second polynomial, we have:

16a^{2} -4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2} =(4-1)(4+1)

So, the second polynomial can be simplified to a difference of squares.

For the third polynomial, we have:

25a^{2} +6a-6a+36=16a^{2}+36=(5a)^{2}+(6)^{2}

So, the third polynomial cannot be simplified to a difference of squares since it's a sum of squares.

Hence, the polynomial that can be simplified to a difference of squares is the second polynomial:

16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}

7 0
3 years ago
Read 2 more answers
Write an equation for the relation.
NeX [460]

Answer:

the answer is f(x)= x-2

8 0
3 years ago
How do I solve this finding the first four of the sequence?
nexus9112 [7]

Answer:

- 7, - 3, 1, 5

Step-by-step explanation:

Using the recursive rule and a₁ = - 7, then

a₂ = a₁ + 4 = - 7 + 4 = - 3

a₃ = a₂ + 4 = - 3 + 4 = 1

a₄ = a₃ + 4 = 1 + 4 = 5

The first four terms are - 7, - 3, 1, 5

4 0
3 years ago
The sum of three consecutive integer is -204. what is the largest integer? -63 --44--67 -62
Lisa [10]
-x + -x-1 + -x-2 = -204
-3x=-201
x=-67

-67-68-69=-204

5 0
3 years ago
As i turned out, avery spent 5 hours per day driving and drove a total of 5565 miles. what was his average speed for the hours h
soldi70 [24.7K]
He drove 1113 per hour.
6 0
3 years ago
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