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2 years ago

An arithmetic sequence has a common difference of 5 and the 3rd term is 15. What is the 5th term?

Mathematics

1 answer:

trapecia [35]2 years ago

3 0

Answer:

an=8n−14

Step-by-step explanation:

for an AP

where

the first term

the common difference

then we have

(

)

(

)

...

(

−

)

we are given the third term

−

(

)

and the fifth term

−

(

)

subtract

(

)

−

(

)

⇒

sub into

(

)

⇒

−

so the nth term

(

−

)

will be

−

(

−

)

−

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The sale price of a pair of shoes is $28. This sale price is 70% of the original price What was the original price?

Veseljchak [2.6K]

Answer:

original price = $40

Step-by-step explanation:

if 70% ---> $28 then

1% ---> $28/70 = $0.4

then we know original price should be 100%

original price = 100 * 0.4 = $40

basic easy function:

(28/70) * 100

$40

5 0

2 years ago

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Find the Jacobian ∂(x, y, z) ∂(u, v, w) for the indicated change of variables. If x = f(u, v, w), y = g(u, v, w), and z = h(u, v

jeyben [28]

Answer:

The Jacobian ∂(x, y, z) ∂(u, v, w) for the indicated change of variables

= -3072uv

Step-by-step explanation:

Step :-(i)

Given x = 1 6 (u + v) …(i)

Differentiating equation (i) partially with respective to 'u'

$\frac{∂x}{∂u} = 16(1)+16(0)=16$

Differentiating equation (i) partially with respective to 'v'

$\frac{∂x}{∂v} = 16(0)+16(1)=16$

Differentiating equation (i) partially with respective to 'w'

$\frac{∂x}{∂w} = 0$

Given y = 1 6 (u − v) …(ii)

Differentiating equation (ii) partially with respective to 'u'

$\frac{∂y}{∂u} = 16(1) - 16(0)=16$

Differentiating equation (ii) partially with respective to 'v'

$\frac{∂y}{∂v} = 16(0) - 16(1)= - 16$

Differentiating equation (ii) partially with respective to 'w'

$\frac{∂y}{∂w} = 0$

Given z = 6uvw ..(iii)

Differentiating equation (iii) partially with respective to 'u'

$\frac{∂z}{∂u} = 6vw$

Differentiating equation (iii) partially with respective to 'v'

$\frac{∂z}{∂v} =6 u (1)w=6uw$

Differentiating equation (iii) partially with respective to 'w'

$\frac{∂z}{∂w} =6 uv(1)=6uv$

Step :-(ii)

The Jacobian ∂(x, y, z)/ ∂(u, v, w) =

$\left|\begin{array}{ccc}16&16&0\\16&-16&0\\6vw&6uw&6uv\end{array}\right|$

Determinant 16(-16×6uv-0)-16(16×6uv)+0(0) = - 1536uv-1536uv

= -3072uv

Final answer:-

The Jacobian ∂(x, y, z)/ ∂(u, v, w) = -3072uv

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devlian [24]

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One parabola with vertex (6, 9) is
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3 years ago

The variables a, b, and c represent polynomials where a = x 1, b = x2 2x − 1, and c = 2x. what is ab c in simplest form?

inna [77]

If you would like to write a * b + c in simplest form, you can do this using the following steps:

a = x + 1
b = x^2 + 2x - 1
c = 2x
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The correct result would be x^3 + 3x^2 + 3x - 1.

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3 years ago

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Fantom [35]

Answer:

0 is the answer

Step-by-step explanation:

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3 years ago