I need help.please

Mathematics

1 answer:

DedPeter [7]4 years ago

5 0

Answer:

1. cos = adjacent / hypotenuse

tan = opposite / adjacent

sin = opposite / hypotenuse

2. cos = adjacent / hypotenuse

cos(G) = 429/821 = 0.5225 ≈ 0.523

tan = opposite / adjacent

tan(G) = 700/429 = 1.6317 ≈ 1.632

sin = opposite / hypotenuse

sin(G) = 700/821 = 0.8526 ≈ 0.853

3. Part A:

sin(G) = opp / hyp = 420/427 = 0.9836 ≈ 0.984

Part B:

tan(Z) = opp / adj = 77 / 420 = 0.1833 ≈ 0.183

Part C:

cos(Z) = adj / hyp = 420 / 427 = 0.9836 ≈ 0.984

Part D:

sin(M) = opp / hyp = 427 / 427 = 1

Part E:

The sine value of any right angle is 1. The opposite side to the right angle is the hypotenuse.

Explanation:

1. Use "SohCahToa" to remember the equations.

S = o/h C = a/h T = o/a

"o" for opposite; "h" for hypotenuse; "a" for adjacent

"S" is sine; "C" is cosine; "T" is tangent.

2. Use the formulas for sin, cos and tan. Substitute the numbers for each side into the equations.

Since the values depend on ∠G, ∠G determines which side is opposite or adjacent. The adjacent side touches ∠G but the opposite side does not. The hypotenuse is the longest side.

3. Use the sin, cos and tan formulas from question 1. Which side is called opposite or adjacent depends on which angle (G, Z or M).

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Zolol [24]

Answer:

$\angle\,JLF = 114^o$ which agrees with option"B" of the possible answers listed

Step-by-step explanation:

Notice that in order to solve this problem (find angle JLF) , we need to find the value of the angle defined by JLG and subtract it from $180^o$ , since they are supplementary angles. So we focus on such, and start by drawing the radii that connects the center of the circle (point "O") to points G and H, in order to observe the central angles that are given to us as $90^o$ and $138^o$ . (see attached image)

We put our efforts into solving the right angle triangle denoted with green borders.

Notice as well, that the triangle JOH that is formed with the two radii and the segment that joins point J to point G, is an isosceles triangle, and therefore the two angles opposite to these equal radius sides, must be equal. We see that angle JOH can be calculated by : $360^o-90^o-138^o=132^o$