Jason is laying out a square garden on his property. The space measures 46 feet diagonally. How long is each side of the garden?

Which of the following sets are subspaces of R3 ?

Ratling [72]

Answer:

The following are the solution to the given points:

Step-by-step explanation:

for point A:

$\to A={(x,y,z)|3x+8y-5z=2} \\\\\to for(x_1, y_1, z_1),(x_2, y_2, z_2) \varepsilon A\\\\ a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)$

$=3(aX_l +bX_2) + 8(ay_1 + by_2) — 5(az_1+bz_2)\\\\=a(3X_l+8y_1- 5z_1)+b (3X_2+8y_2—5z_2)\\\\=2(a+b)$

The set A is not part of the subspace $R^3$

for point B:

$\to B={(x,y,z)|-4x-9y+7z=0}\\\\\to for(x_1,y_1,z_1),(x_2, y_2, z_2) \varepsilon B \\\\\to a(x_1, y_1, z_1)+b(x_2, y_2, z_2) = (ax_1+bx_2,ay_1+by_2,az_1+bz_2)$

$=-4(aX_l +bX_2) -9(ay_1 + by_2) +7(az_1+bz_2)\\\\=a(-4X_l-9y_1+7z_1)+b (-4X_2-9y_2+7z_2)\\\\=0$

$\to a(x_1,y_1,z_1)+b(x_2, y_2, z_2) \varepsilon B$

The set B is part of the subspace $R^3$

for point C: $\to C={(x,y,z)|x$

In this, the scalar multiplication can't behold

$\to for (-2,-1,2) \varepsilon C$

$\to -1(-2,-1,2)= (2,1,-1)$ ∉ C

this inequality is not hold

The set C is not a part of the subspace $R^3$

for point D:

$\to D={(-4,y,z)|\ y,\ z \ arbitrary \ numbers)$

The scalar multiplication s is not to hold

$\to for (-4, 1,2)\varepsilon D\\\\\to -1(-4,1,2) = (4,-1,-2)$ ∉ D

this is an inequality, which is not hold

The set D is not part of the subspace $R^3$

For point E:

$\to E= {(x,0,0)}|x \ is \ arbitrary) \\\\\to for (x_1,0 ,0) ,(x_{2},0 ,0) \varepsilon E \\\\\to a(x_1,0,0) +b(x_{2},0,0)= (ax_1+bx_2,0,0)\\$

The $x_1, x_2$ is the arbitrary, in which $ax_1+bx_2$ is arbitrary

$\to a(x_1,0,0)+b(x_2,0,0) \varepsilon E$

The set E is the part of the subspace $R^3$

For point F:

$\to F= {(-2x,-3x,-8x)}|x \ is \ arbitrary) \\\\\to for (-2x_1,-3x_1,-8x_1),(-2x_2,-3x_2,-8x_2)\varepsilon F \\\\\to a(-2x_1,-3x_1,-8x_1) +b(-2x_1,-3x_1,-8x_1)= (-2(ax_1+bx_2),-3(ax_1+bx_2),-8(ax_1+bx_2))$

The $x_1, x_2$ arbitrary so, they have $ax_1+bx_2$ as the arbitrary $\to a(-2x_1,-3x_1,-8x_1)+b(-2x_2,-3x_2,-8x_2) \varepsilon F$

The set F is the subspace of $R^3$

5 0

3 years ago

Help me please, I’ve been stuck on this. :(

maxonik [38]

Answer: 0.98 cents

Step-by-step explanation:

First you want to get the amount of apples to one pound.

3.5 to 1

3.5 divided by 3.5 equals to one.

Now you need to o the same thing to the cost

3.43 divided by 3.5

= 0.98

since we are talking money it would be 0.98 cents

4 0

3 years ago

The question has a period I don’t know why

Xelga [282]

It is not a question it’s telling you to do it haha! But just divide the (hours of / days) for example 7/2 and that would be your answer!

7 0

3 years ago

Can anyone help me with this?

faltersainse [42]

Answer:

a

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

I WILL MARK AS BRAINLIEST! Solve the following

deff fn [24]

Answer:

6)

a. x=35

b. x=4

c. x=30

Step-by-step explanation:

6a) 7/9=x/45

7/9×45=x

7×45/9=x

315/9=x

35=x

x=35

————————

b. 10/8=5/x

5/4=5/x

5/4x=5(the x is in the middle of the division sign here)

5x/4=5(the x is NOT in the middle of the division sign)

5x=5×4

5x=20

x=20/5

x=4

———————

c. x/34=15/17

x=15/17×34

x=15×34/17

x=510/17

x=30

hope that helped you. I can't answer number 7, I'm sorry

7 0

2 years ago

Read 2 more answers